PHP, Get tomorrows date from date

Question

I have a PHP date in the form of 2013-01-22 and I want to get tomorrows date in the same format, so for example 2013-01-23.

How is this possible with PHP?

Answer 1

Use DateTime

$datetime = new DateTime('tomorrow');
echo $datetime->format('Y-m-d H:i:s');

Or:

$datetime = new DateTime('2013-01-22');
$datetime->modify('+1 day');
echo $datetime->format('Y-m-d H:i:s');

Or:

$datetime = new DateTime('2013-01-22');
$datetime->add(new DateInterval("P1D"));
echo $datetime->format('Y-m-d H:i:s');

Or in PHP 5.4+:

echo (new DateTime('2013-01-22'))->add(new DateInterval("P1D"))
                                 ->format('Y-m-d H:i:s');

Answer 2

 $tomorrow = date("Y-m-d", strtotime('tomorrow'));

or

  $tomorrow = date("Y-m-d", strtotime("+1 day"));

Help Link: STRTOTIME()

Answer 3

Since you tagged this with strtotime, you can use it with the +1 day modifier like so:

$tomorrow_timestamp = strtotime('+1 day', strtotime('2013-01-22'));

That said, it's a much better solution to use DateTime.

Answer 4

<? php 

//1 Day = 24*60*60 = 86400

echo date("d-m-Y", time()+86400); 

?>

Answer 5

echo date ('Y-m-d',strtotime('+1 day', strtotime($your_date)));

Answer 6

Use DateTime:

To get tomorrow from now :

$d = new DateTime('+1day');
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;

Results : 28/06/2017 08.13.20

To get tomorrow from a date :

$d = new DateTime('2017/06/10 08.16.35 +1day')
$tomorrow = $d->format('d/m/Y h.i.s');
echo $tomorrow;

Results : 11/06/2017 08.16.35

Hope it helps!

Answer 7

/**
 * get tomorrow's date in the format requested, default to Y-m-d for MySQL (e.g. 2013-01-04)
 *
 * @param string
 *
 * @return string
 */
public static function getTomorrowsDate($format = 'Y-m-d')
{
    $date = new DateTime();
    $date->add(DateInterval::createFromDateString('tomorrow'));

    return $date->format($format);
}

Answer 8

By strange it can seem it works perfectly fine: date_create( '2016-02-01 + 1 day' );

echo date_create( $your_date . ' + 1 day' )->format( 'Y-m-d' );

Should do it

Answer 9

here's working function

function plus_one_day($date){
 $date2 = formatDate4db($date);
 $date1 = str_replace('-', '/', $date2);
 $tomorrow = date('Y-m-d',strtotime($date1 . "+1 days"));
 return $tomorrow; }

Answer 10

$date = '2013-01-22';
$time = strtotime($date) + 86400;
echo date('Y-m-d', $time);

Where 86400 is the # of seconds in a day.