How to test style for a React component attribute with Enzyme

问题

I am trying to test a style attribute for a React component. What is the best way to get style params in the test?

At this moment, my best option is to test if the HTML includes the string, but I think there is a better option.

Case:

it('Should render large image when desktop', () => {
    const dummyUrl = 'http://dummyUrl';
    const wrapper = shallow(
      <MockedStore
        initialState={{
          app: fromJS({ browser: { desktop: true } }),
        }}
      >
        <LandingHero bigImage={dummyUrl} />
      </MockedStore>
    );
  });

The Component to test is:

// @flow
import React, { Component } from 'react';
import gc from 'styles/core.scss';
import $ from 'jquery';
import DownloadButton from 'components/DownloadButton';
import withStyles from 'isomorphic-style-loader/lib/withStyles';
import DownArrow from 'components/DownArrow';
import { connect } from 'react-redux';
import type { Map } from 'immutable';
import c from './styles.scss';

@withStyles([gc, c])
@connect(({ app }) => ({ app }))
class LandingHero extends Component {
  componentDidMount() {
    if ($(window).height() > 0) { // Necesary for webpack dev server
      $(this.hero).css('height', $(window).height() - 46);
    }
  }

  hero: HTMLElement;

  props: {
    app: Map<string, any>,
    copy: string,
    secondaryText: string,
    thirdText: string,
    bigImage?: string,
    smallImage: string,
  }

  render() {
    const { copy, secondaryText, thirdText } = this.props;
    const browser = this.props.app.has('browser') ? this.props.app.get('browser') : {};
    const backgroundImage = browser.desktop ? this.props.bigImage : this.props.smallImage;

    return (
      <div
        className={`${c.hero} ${gc.textCenter}` +
        ` ${gc.alignMiddle} ${gc.alignCenter} ${gc.row} ${gc.expanded}`}
        ref={(hero) => { this.hero = hero; }}
        style={{
          margin: 0,
          position: 'relative',
          background: `linear-gradient(to bottom, rgba($ixdarkprimary, .3), rgba($ixdarkprimary, .3)), url(${backgroundImage || ''})`,
        }}
      >
        <div className={`${gc.row} ${gc.alignCenter} ${gc.alignMiddle} ${gc.column} ${gc.medium10}`}>
          <div className={`${gc.textCenter}`}>
            <div
              className={`${gc.white} ${c.mainText} ${c.copy}`}
            >
              { copy }
            </div>
            <div className={`${gc.small6} ${gc.smallOffset3} ${gc.medium4} ${gc.mediumOffset4}`} style={{ marginBottom: 45 }}>
              <DownloadButton />
            </div>
            <div className={`${gc.white} ${gc.fontBold} ${gc.font24}`}>{secondaryText}</div>
            <p className={`${gc.white} ${gc.font20}`}>{thirdText}</p>
          </div>
          <DownArrow goTo="#content" />
        </div>
      </div>
    );
  }
}

export default LandingHero;

回答1:

You can use this method. It returns ReactElement.

let containerStyle = container.get(0).style;
expect(containerStyle).to.have.property('opacity', '1');

回答2:

Slightly elaborating on others' answers:

expect(component.find('#item-id').prop('style')).toHaveProperty('backgroundSize', '100%');

This will check the style prop of #item-id. This prop is an object and here toHaveProperty matcher checks if this object contains backgroundSize property and if its value is 100%.

This way other style properties are ignored.

回答3:

expect(component.find('#item-id').prop('style')).to.deep.equal({display: 'none'})

回答4:

If you use jest-styled-components then you can use toHaveStyleRule as follows:

expect(component.find('#item-id')).toHaveStyleRule('opacity', 'red');

回答5:

const elem = wrapper.find(Element);
expect(getComputedStyle(elem.getDOMNode()).getPropertyValue('opacity')).toBe('0.4');

回答6:

Have a look at chaiEnzyme, which provides a handy little assertion you can use with chai to check whether a wrapper has a particular style (https://github.com/producthunt/chai-enzyme#stylekey-val), should help make your tests look a little cleaner.

回答7:

You can try using a regex on .html() value:

const span = mount(<Test />).find('span');
expect(span.html().match(/style="([^"]*)"/i)[1]).toBe('color: #000;');

Or to get any other attribute:

const getAttr = ( html, name ) => html.match(new RegExp(`${name}="([^"]*)"`, 'i'))[1];
let type = getAttr('<input type="text" value=""/>', 'type');
console.log(type);  // "text"

回答8:

I would like to add that the following props() method can also be used. https://airbnb.io/enzyme/docs/api/ShallowWrapper/props.html

let containerStyleOpacity = container.get(0).props().style.opacity; expect(containerStyleOpacity).to.be.equal('1');

来源：https://stackoverflow.com/questions/40795850/how-to-test-style-for-a-react-component-attribute-with-enzyme

标签

reactjs

enzyme