问题
I'm stumped on what seemed to be a simple UPDATE statement.
I'm looking for an UPDATE that uses two values. The first (a) is used to group, the second (b) is used to find a local minimum of values within the respective group. As a little extra there is a threshold value on b: Any value 1 or smaller shall remain as it is.
drop table t1;
create table t1 (a number, b number);
insert into t1 values (1,0);
insert into t1 values (1,1);
insert into t1 values (2,1);
insert into t1 values (2,2);
insert into t1 values (3,1);
insert into t1 values (3,2);
insert into t1 values (3,3);
insert into t1 values (4,1);
insert into t1 values (4,3);
insert into t1 values (4,4);
insert into t1 values (4,5);
-- 1,0 -> 1,0
-- 1,1 -> 1,1
-- 2,1 -> 2,1
-- 2,2 -> 2,2
-- 3,1 -> 3,1
-- 3,2 -> 3,2
-- 3,3 -> 3,2 <-
-- 4,1 -> 4,1
-- 4,3 -> 4,3 <-
-- 4,4 -> 4,3 <-
-- 4,5 -> 4,3 <-
Obviously not sufficient is:
update t1 x
set b = (select min(b) from t1 where b > 1)
;
Whatever more complicated stuff I try, e.g.
UPDATE t1 x
set (a,b) = (select distinct a,b from (
select a, min(b) from t1 where b > 1 group by a)
)
;
I get SQL-Fehler: ORA-01427: Unterabfrage für eine Zeile liefert mehr als eine Zeile 01427. 00000 - "single-row subquery returns more than one row"
which is not overly surprising as I need a row for each value of a.
Of course I could write a PL/SQL Procedure with a cursor loop but is it possible in a single elegant SQL statement? Maybe using partition by?
回答1:
Your question is a bit confusing.
You say that you would like to set value b to a minimum value from partition a that column b is in row with, while the rows containing b = 1 should remain untouched.
From what I can see in your question as comments (I assume it's your expected output) you also want to get the minimum value that follows 1 within a partition - so you basically want the minimum value of b that is greater than 1.
Below is SQL query that does this
UPDATE t1 alias
SET b = (
SELECT min(b)
FROM t1
WHERE alias.a = t1.a
AND t1.b > 1 -- this would get the minimum value higher than 1
GROUP BY a
)
WHERE alias.b > 1 -- update will not affect rows with b <= 1
Output after update
a | b
---+---
1 | 0
1 | 1
2 | 1
2 | 2
3 | 1
3 | 2
3 | 2
4 | 1
4 | 3
4 | 3
4 | 3
来源:https://stackoverflow.com/questions/29692077/update-with-group-by