问题
I am pretty new to html5 web development
I have created a page with login and password on it and have a submit button. On submit , I send a rest request to the server which has a url
THE RRQUEST IS SOMETHING LIKE THIS
<USERNAME>
abc
</USERNAME>
<PASSWORD>loooik
</PASSWORD>
which is in js file as var data...
This request is set as
var parameters=JSON.stringify(data);
I use the following code for establishing connection
xmlHttp.open("post",url,true);
XmlHttp.setRequestHeader("Content-type","application/json);
xmlHttp.send(parameters);
xmlHttp.onreadystatechange=function X()
{
if(xmlHttp.readyState==4)
{
alert(xmlHttp.responseText);
}
}
return true;
}
I need to add a loading element and want to display the next screen between request and the response. How can I achieve it?
In tag I have used submit input type where onClick attribute calls return sendPost() method which has the request to be called
How should I proceed for the same... having loading screen and getting the response ... suppose just the name to be displayed on next html screen
回答1:
First of all see basic jQuery example. This will guide you through how jQuery works and help a lot in the solution I'm going to suggest.
http://learn.jquery.com/about-jquery/how-jquery-works/
jQuery has it's own AJAX method and further shorthand called $.post
Now you can write something like this -
function requestNetwork() {
// Code for loading screen
$.ajax({
url: "yourURL",
data: "yourData"
}).done(function(data) {
alert(xmlHttp.responseText);
// Code for dismissing loading screen
}).fail(function(data) {
// Code when call fails
}).always(function() {
// This code will always run
});
}
来源:https://stackoverflow.com/questions/21570283/html5-request-response-webservice