How to make a path that has variable input in the middle read in a input file in python

问题

This should be pretty easy, not sure why I can't get it to work. I am trying to import a ton of .txt files as part of a larger process like so:

    path = "C:/Users/A/B/"

    with open(path + "*full.txt","r") as f:
        contents =f.read()
        print(contents)

I am just trying to import all .txt files (there are a ton of them) in this folder path, when I do this I get:

OSError: [Errno 22] Invalid argument:

There are strings in the middle that are different between each file hence the * before the full it lists the path after argument (for privacy reasons I will leave it out but you get the point) and I know that the path is correct, why is it giving me this error?

回答1:

You can't use * in open(). open() can open only one file with exact name.

You have to get all names in directory and use for-loop to open every file separatelly.

With glob.glob():

import glob

path = "C:/Users/A/B/"

for fullname in glob.glob( path + "*full.txt" ):
    with open(fullname, "r") as f:
        contents = f.read()
        print(contents)

With os.listdir():

import os

path = "C:/Users/A/B/"

for name in os.listdir(path):
    if name.endswith("full.txt"):
        fullname = os.path.join(path, name):
        with open(fullname, "r") as f:
            contents = f.read()
            print(contents)