问题
In the code bellow, I'm searching for ways to optimize the speed of insertions when dealing with Millions of inserts at the time. the code runs fine but is very slow when performing large amounts of inserts. I already tried some ideas but is always slow. I guess the solution is to use Multi-threading to perform the inserts, and use a global variable "truct Node* nodeObj". I have very few/no experience with Multi-threading and Synchronization in C, C++, If you could give me an example based on the code bellow I would be very appreciated. Any additional Ideas are welcome.
The rules are: 1- In the end (after insert all numbers) the linked list must be ordered, meaning that each Node->data starts at lowest number up to the Largest number. 2 - The caller is using a for loop, this for loop cannot be started inside the Insert function. 3 - Any of the code, caller or insert function can be optimized as long as the insert function does not automatically add inserts by it self, that's the caller s job.
#include<stdio.h>
#include<stdlib.h>
#include<conio.h>
struct Node {
int data;
struct Node* nextAddr;
};
struct Node* Insert(Node* p, int data);
void Print(struct Node* p);
void RevPrint(struct Node* p);
int main() {
struct Node* nodeObj = NULL;
printf("---------------------------------\n"
"Insert()\n---------------------------------\n");
for (int i = 1; i < 1000000; i++) {
nodeObj = Insert(nodeObj, i);
printf(" %d", i);
}
printf("\n---------------------------------\n"
"Print()\n---------------------------------\n");
Print(nodeObj);
printf("---------------------------------\n"
"RevPrint()\n---------------------------------");
RevPrint(nodeObj);
printf("\nPress any key to continue...");
_getch();
}
struct Node* Insert(Node* _pToNode, int _nbr)
{
Node *newValue = (struct Node*)malloc(sizeof(struct Node));
newValue->data = _nbr;
newValue->nextAddr = NULL;
if (_pToNode == NULL) _pToNode = newValue;
else {
Node* pLocal = _pToNode;
while (pLocal->nextAddr != NULL) {
pLocal = pLocal->nextAddr;
}
pLocal->nextAddr = newValue;
}
return _pToNode;
}
void Print(struct Node* p) {
if (p == NULL) {
printf("\n");
return;
}
printf(" %d", p->data);
Print(p->nextAddr);
}
void RevPrint(struct Node* p) {
if (p == NULL) {
printf("\n");
return;
}
RevPrint(p->nextAddr);
printf(" %d", p->data);
}
Thank you.
回答1:
Caveat: This works only for tail insertion/append:
int
main()
{
struct Node* nodeObj = NULL;
struct Node* nodeTail = NULL;
// your other stuff ...
for (int i = 1; i < 1000000; i++) {
nodeObj = Insert(nodeObj, &nodeTail, i);
printf(" %d", i);
}
// your other stuff ...
}
struct Node* Insert(Node* _pToNode, Node **tail,int _nbr)
{
Node *newValue = (struct Node*)malloc(sizeof(struct Node));
newValue->data = _nbr;
newValue->nextAddr = NULL;
if (_pToNode == NULL) {
_pToNode = newValue;
}
else {
(*tail)->nextAddr = newValue;
}
*tail = newValue;
return _pToNode;
}
You could clean this up with a "list" struct that has both the head and tail in it (vs. the separate args)
UPDATE:
Very cool/smart, but unfortunately is still slow...
malloc et. al. can be slow for a large number of small allocations. One way to speed things up is to use a subpool of allocations [as WeatherVane suggested].
As I mentioned, adding a "list" struct can make things tidier and I used it in two places. Once you commit to that, you can add other things besides head/tail, such as count. Also, it makes it easier to convert from a singly-linked list to a doubly-linked in the future, if you so choose.
Side note: With a doubly-linked list, insertions are [slightly] more complex, but insertions in the middle of the list are much faster because you don't have to traverse the list to find the previous pointer (e.g. the node would have a prev pointer in it). Also, RevPrintList would become as simple as PrintList.
Note that [on my system], the reverse print ran out of stack space [and segfaulted], so I recoded the print functions to not be recursive.
Here's a cleaned up version that should do the insertions faster because of the reduced number of individual malloc calls.
Side note: I didn't add the requisite checks for malloc, etc. returning null.
#include <stdio.h>
#include <stdlib.h>
//#include <conio.h>
typedef struct Node_ {
int data;
struct Node_* next;
} Node;
typedef struct List_ {
int count;
Node* head;
Node* tail;
} List;
Node* NewNode(void);
Node* Insert(List* p, int data);
void Print(Node* p);
void PrintList(List *list);
void RevPrint(Node* p);
void RevPrintList(List *list);
List freelist;
int
main()
{
List nodelist = { 0, NULL, NULL };
printf("---------------------------------\n"
"Insert()\n---------------------------------\n");
for (int i = 1; i < 1000000; i++) {
Insert(&nodelist, i);
#if 0
printf(" %d", i);
#endif
}
printf("\n---------------------------------\n"
"Print()\n---------------------------------\n");
#if 0
Print(nodelist.head);
#else
PrintList(&nodelist);
#endif
printf("---------------------------------\n"
"RevPrint()\n---------------------------------");
#if 0
RevPrint(nodelist.head);
#else
RevPrintList(&nodelist);
#endif
printf("\nPress any key to continue...");
#if 0
_getch();
#else
getchar();
#endif
}
Node*
NewNode(void)
{
Node *node;
// NOTE: adjust the count setup (e.g. 1000) to what ever value you want
if (freelist.count <= 0) {
freelist.count = 1000;
freelist.head = calloc(freelist.count,sizeof(Node));
}
node = freelist.head++;
freelist.count -= 1;
return node;
}
Node*
Insert(List* list,int _nbr)
{
Node *node = NewNode();
node->data = _nbr;
node->next = NULL;
if (list->head == NULL) {
list->head = node;
}
else {
list->tail->next = node;
}
list->tail = node;
list->count += 1;
return node;
}
void
Print(Node* p)
{
if (p == NULL) {
printf("\n");
return;
}
printf(" %d", p->data);
Print(p->next);
}
void
PrintList(List* list)
{
Node *node;
for (node = list->head; node != NULL; node = node->next)
printf(" %d", node->data);
printf("\n");
}
void
RevPrint(Node* p)
{
if (p == NULL) {
printf("\n");
return;
}
RevPrint(p->next);
printf(" %d", p->data);
}
void
RevPrintList(List *list)
{
Node **rlist = malloc(sizeof(Node**) * list->count);
Node *node;
int ridx;
ridx = list->count - 1;
for (node = list->head; node != NULL; node = node->next, --ridx)
rlist[ridx] = node;
for (ridx = 0; ridx < list->count; ++ridx) {
node = rlist[ridx];
printf(" %d",node->data);
}
printf("\n");
free(rlist);
}
UPDATE #2:
you could make freeList a list of lists (using a different "node" struct which would have a pointer to list instead of a number), so that memory could be released when the program is done.
Here is a modified version that does that:
#include <stdio.h>
#include <stdlib.h>
//#include <conio.h>
typedef struct Node_ {
int data;
struct Node_* next;
} Node;
typedef struct List_ {
int count;
Node* head;
Node* tail;
} List;
typedef struct Freelist_ {
int count;
Node* head;
Node* tail;
Node* avail;
} FreeList;
Node* NewNode(void);
Node* Insert(List* p, int data);
void Print(Node* p);
void PrintList(List *list);
void RevPrint(Node* p);
void RevPrintList(List *list);
void FreeAll(void);
FreeList freelist = { 0 };
int
main()
{
List nodelist = { 0, NULL, NULL };
printf("---------------------------------\n"
"Insert()\n---------------------------------\n");
for (int i = 1; i < 1000000; i++) {
Insert(&nodelist, i);
// this printf will radically slow things down
#if 0
printf(" %d", i);
#endif
}
printf("\n---------------------------------\n"
"Print()\n---------------------------------\n");
#if 0
Print(nodelist.head);
#else
PrintList(&nodelist);
#endif
printf("---------------------------------\n"
"RevPrint()\n---------------------------------");
#if 0
RevPrint(nodelist.head);
#else
RevPrintList(&nodelist);
#endif
// release all nodes back to the malloc free pool
FreeAll();
printf("\nPress any key to continue...");
#if 0
_getch();
#else
getchar();
#endif
}
Node*
NewNode(void)
{
Node *node;
// NOTE: adjust the count setup (e.g. 1000) to what ever value you want
if (freelist.count <= 0) {
freelist.count = 1000;
node = calloc(freelist.count,sizeof(Node));
// maintain linked list of nodes that are at the _start_ of a
// malloc area/arena
if (freelist.head == NULL)
freelist.head = node;
else
freelist.tail->next = node;
freelist.tail = node;
// burn the first node as a placeholder
freelist.avail = node + 1;
freelist.count -= 1;
}
node = freelist.avail++;
freelist.count -= 1;
return node;
}
void
FreeAll(void)
{
Node* node;
Node* next;
for (node = freelist.head; node != NULL; node = next) {
next = node->next;
free(node);
}
}
Node*
Insert(List* list,int _nbr)
{
Node *node = NewNode();
node->data = _nbr;
node->next = NULL;
if (list->head == NULL) {
list->head = node;
}
else {
list->tail->next = node;
}
list->tail = node;
list->count += 1;
return node;
}
void
Print(Node* p)
{
if (p == NULL) {
printf("\n");
return;
}
printf(" %d", p->data);
Print(p->next);
}
void
PrintList(List* list)
{
Node *node;
for (node = list->head; node != NULL; node = node->next)
printf(" %d", node->data);
printf("\n");
}
void
RevPrint(Node* p)
{
if (p == NULL) {
printf("\n");
return;
}
RevPrint(p->next);
printf(" %d", p->data);
}
void
RevPrintList(List *list)
{
Node **rlist = malloc(sizeof(Node**) * (list->count + 1));
Node *node;
int ridx;
ridx = list->count - 1;
for (node = list->head; node != NULL; node = node->next, --ridx)
rlist[ridx] = node;
for (ridx = 0; ridx < list->count; ++ridx) {
node = rlist[ridx];
printf(" %d",node->data);
}
printf("\n");
free(rlist);
}
UPDATE #3:
Here's a version that adds reuse of nodes by adding a reuse member to FreeList and a FreeOne function that can be called when a node is deleted.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
//#include <conio.h>
typedef struct Node_ {
int data;
struct Node_ *next;
} Node;
typedef struct List_ {
int count;
Node *head;
Node *tail;
} List;
typedef struct Freelist_ {
int count;
Node *head;
Node *tail;
Node *avail;
Node *reuse;
} FreeList;
Node *NewNode(void);
Node *Insert(List *p,int data);
void Print(Node *p);
void PrintList(List *list);
void RevPrint(Node *p);
void RevPrintList(List *list);
void FreeOne(Node *p);
void FreeAll(void);
FreeList freelist = { 0 };
int
main()
{
List nodelist = { 0, NULL, NULL };
printf("---------------------------------\n" "Insert()\n---------------------------------\n");
for (int i = 1; i < 1000000; i++) {
Insert(&nodelist,i);
// this printf will radically slow things down
#if 0
printf(" %d",i);
#endif
}
printf("\n---------------------------------\n" "Print()\n---------------------------------\n");
#if 0
Print(nodelist.head);
#else
PrintList(&nodelist);
#endif
printf("---------------------------------\n" "RevPrint()\n---------------------------------");
#if 0
RevPrint(nodelist.head);
#else
RevPrintList(&nodelist);
#endif
// release all nodes back to the malloc free pool
FreeAll();
printf("\nPress any key to continue...");
#if 0
_getch();
#else
getchar();
#endif
}
Node *
NewNode(void)
{
FreeList *list;
Node *node;
list = &freelist;
do {
// try to reuse a node that has been released by FreeOne
node = list->reuse;
if (node != NULL) {
list->reuse = node->next;
node->next = NULL;
break;
}
// NOTE: adjust the count setup (e.g. 1000) to what ever value you want
if (list->count <= 0) {
list->count = 1000;
node = calloc(list->count,sizeof(Node));
// maintain linked list of nodes that are at the _start_ of a
// malloc area/arena
if (list->head == NULL)
list->head = node;
else
list->tail->next = node;
list->tail = node;
// burn the first node as a placeholder
list->avail = node + 1;
list->count -= 1;
}
// grab one from the current allocation array
node = list->avail++;
list->count -= 1;
} while (0);
return node;
}
void
FreeOne(Node *node)
{
FreeList *list;
list = &freelist;
// push this node onto the front of the reuse list (i.e. it's fast)
node->next = list->reuse;
list->reuse = node;
}
void
FreeAll(void)
{
Node *node;
Node *next;
for (node = freelist.head; node != NULL; node = next) {
next = node->next;
free(node);
}
memset(&freelist,0,sizeof(FreeList));
}
Node *
Insert(List *list,int _nbr)
{
Node *node = NewNode();
node->data = _nbr;
node->next = NULL;
if (list->head == NULL) {
list->head = node;
}
else {
list->tail->next = node;
}
list->tail = node;
list->count += 1;
return node;
}
void
Print(Node *p)
{
if (p == NULL) {
printf("\n");
return;
}
printf(" %d",p->data);
Print(p->next);
}
void
PrintList(List *list)
{
Node *node;
for (node = list->head; node != NULL; node = node->next)
printf(" %d",node->data);
printf("\n");
}
void
RevPrint(Node *p)
{
if (p == NULL) {
printf("\n");
return;
}
RevPrint(p->next);
printf(" %d",p->data);
}
void
RevPrintList(List *list)
{
Node **rlist = malloc(sizeof(Node **) * (list->count + 1));
Node *node;
int ridx;
ridx = list->count - 1;
for (node = list->head; node != NULL; node = node->next, --ridx)
rlist[ridx] = node;
for (ridx = 0; ridx < list->count; ++ridx) {
node = rlist[ridx];
printf(" %d",node->data);
}
printf("\n");
free(rlist);
}
回答2:
Linked lists are unwelcome on modern machines. The L1 and L2 caches love vectors and arrays. They utterly despise linked lists. Use a std::vector, not a linked list, (and certainly not a hand-rolled linked list). Try to .reserve() enough memory in the vector to accommodate all the new stuff. Just push everything onto the back of the vector, and then sort the vector using parallel execution. C++17 can do that painlessly. std::stable_sort parallels quite nicely.
回答3:
I assume that the order of the elements that you mention is ordered by comparison. I.e. A < B => A is before B in the container.
If that assumption holds the best you can hope for is a log(N) insertion of each element. So if you want to insert an element among those millions of elements you should expect to do about 20+ comparisons. If the millions you want to insert have an order you can do better.
Now, a pointer based structure is never the answer to a fast data structure. std::vector should be your go to.
To read this fast-insertion structure with a for statement you'd need a very peculiar iterator or you need to rearrange the inserted stuff in to another vector.
In conclusion, you want to insert stuff into a simple binary heap.
Multithreading would not make this faster unless you can devise a merge like scheme to your inserts.
来源：https://stackoverflow.com/questions/49581934/slow-inserts-linked-list-multi-threading-needed