How to get a password with a CLI program?

问题

I am writing a Linux CLI program. I need to get a password from the user and, obviously, I don't want the password to be echoed to the console.

There are several solutions available here, but they are all for plain C. C command-line password input
How to mask password in c?
Getting a password in C without using getpass (3)?

How can those be adapted for C++, using std::string instead of char[]?

What would be the most elegant C++ solution?

回答1:

Use any of the plain C solutions:

std::string pass (100);  // size the string at your max password size (minus one)

func_to_get_pass(&pass[0], pass.size());
// function takes a char* and the max size to write (including a null char)

pass.resize(pass.find('\0'));

cout << "Your password is " << pass << ".\n"; // oops! don't show it ;)

回答2:

Linux itself is written (mostly) in C, so anything you could find in C++ would only be an abstraction around a single C routine. Better to call the routine yourself, converting the input and result.

来源：https://stackoverflow.com/questions/4050757/how-to-get-a-password-with-a-cli-program