问题
I'm creating a web site directory for my mobile site (FOUND HERE)
I have figured out how to display listings from my mysql table to my home page from my tables promo_cat list.
The thing im having trouble with is this:
once clicking on one of the catagories it leads me to my list.php page.
How do I get this page to display results related to the category clicked and not others?
For example:when clicking on "FREE" brings up this page: http://www.xclo.mobi/xclo2/list.php?id=FREE. Which displays all results. it should only display results that have a promo_cat field as "FREE" and should not display any other results as it does currently.
My list.php code:
<?php
include_once('include/connection.php');
include_once('include/article.php');
$article = new article;
$articles = $article->fetch_all();
?>
<html>
<head>
<title>xclo mobi</title>
<link rel="stylesheet" href="other.css" />
</head>
<body>
<?php include_once('header.html'); ?>
<div class="container">
<a href="index.php" id="logo">Category = ???</a>
<ol>
<?php foreach ($articles as $article) { ?>
<div class="border">
<a href="single.php?id=<?php echo $article['promo_title']; ?>" style="text-decoration: none">
<img src="<?php echo $article['promo_image']; ?>" border="0" class="img" align="left"><br />
<a href="<?php echo $data['promo_link']; ?>" target="_blank"><img alt="" title="" src="GO.png" height="50" width="50" align="right" /></a>
<font class="title"><em><center><?php echo $article['promo_title']; ?></center></em></font>
<br /><br />
<font class="content"><em><center><?php echo $article['promo_content']; ?></center></em></font>
</div><br/><br />
</a>
<?php } ?>
</ol>
</div>
</body>
</html>
/include/article.php
<?php
class article {
public function fetch_all(){
global $pdo;
$query = $pdo->prepare("SELECT * FROM mobi");
$query->execute();
return $query->fetchAll();
}
public function fetch_data($promo_title) {
global $pdo;
$query = $pdo->prepare("SELECT * FROM mobi WHERE promo_title = ?");
$query->bindValue(1, $promo_title);
$query->execute();
return $query->fetch();
}
}
?>
回答1:
Based on the code you provided, try this:
<?php foreach ($articles as $article) {
if ($article['promo_cat'] === 'FREE') { ?>
// Keep the rest of the code
//instead of <?php } ?> - put...
<?php } } ?>
Keep in mind, this is messy. But the foreach
statement (I imagine) is being used to print out all posts. So, before printing out a post, you just check to see if the promo_title is FREE, GIFT, etc. If it's not, then it doesn't print that item.
You can make this more dynamic by passing in a $_GET variable (which you apparently are doing, but the code is never using this variable) with the current promo title and altering the conditional line to say
if ($article['promo_cat'] === $_GET['id'])
Hope that helps!
回答2:
You need to make changes to the code for list.php based on the input it gets through GET parameter. something like:
if ($_GET['id'] == 'FREE'){
// do something like display FREE items
}
elseif($_GET['id'] == 'GIFT') {
// display GIFT items
}
else {
// perform some default action
}
This is to make it even more database driven (helpful when there are many categories):
$sql = "select * from categories where id = '".$_GET['id']."'";
if (mysql_results($sql)){
// do something
}
else {
// show error
}
Note that this is for demo only and in your code you should use PDO/MySQLI and prepared statements and not mysql_results function.
In light of more information provided by OP: Change this
$articles = $article->fetch_all();
to
$articles = $article->fetch_data($_GET['id']);
in list.php and see if you get correct results.
来源:https://stackoverflow.com/questions/17751536/displaying-accurate-results