问题
I'm looking to run some R code on python
I already installed the R package robustbase on ubunto using apt-get install r-cran-robustbase and rpy packege as well.
from the python console I can successfully run from rpy import * and r.library("robustbase")
but when I run
result = robjects.FloatVector([11232.1, 234.2, 3445532344.3, 34302.3, 203.9, 232223.3, 3434.55])
print(result.r_repr())
r(adjboxStats(c(11232.1, 234.2, 3445532344.3, 34302.3, 203.9, 232223.3, 3434.55), coef = 2.5, a = -4, b = 3, do_conf = TRUE, do_out = TRUE))
to get the outliers values
But I get this error :
adjboxStats(c(11232.1, 234.2, 3445532344.3, 34302.3, 203.9, 232223.3, 3434.55), coef = 2.5, a = -4, b = 3, do.conf = TRUE, do.out = TRUE)
SyntaxError: keyword can't be an expression
when I run this on R console it works!!!
library("robustbase")
adjboxStats(c(11232.1, 234.2, 3445532344.3, 34302.3, 203.9, 232223.3, 3434.55), coef = 2.5, a = -4, b = 3, do.conf = TRUE, do.out = TRUE)
I search here , here and here but no luck. doesn anyone knows what is that error message for and is there's a way to go arround it?
Thanks!
回答1:
You can't use do.conf or do.out as arguments to a Python function (even if the function will be converted to R).
Instead, call them do_conf and do_out. You were then getting tripped up by another error, which is how you refer to r("adjboxStats"):
r("adjboxStats")(result, coef = 2.5, a = -4, b = 3, do_conf = True, do_out = True)
This will fix the syntax issues.
来源：https://stackoverflow.com/questions/16551373/runing-r-code-on-python-with-syntaxerror-keyword-cant-be-an-expression-error