问题
Trying to figure out the Regex pattern to match if an email contains a Guid, e.g.
a141aa94-3bec-4b68-b562-6b05fc2bfa48-reply@site.com
The Guid could potentially be anywhere before the @, e.g.
reply-a141aa94-3bec-4b68-b562-6b05fc2bfa48@wingertdesign.com
回答1:
I use this to find Guids
Regex isGuid = new Regex(@"^(\{){0,1}[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}(\}){0,1}$", RegexOptions.Compiled);
回答2:
A lazy variant would be
([0-9a-f-]{36}).*?@
It is easy to read and I bet it matches 99,99% of all cases ;) But then in 0,00001% of all cases sombody could have an email address that fits in a GUID scheme.
回答3:
Well, assuming it's always going to be in standard GUID notation like that, if the following regex matches there was a GUID. You should also apply your language's method of making it case-insensitive.
[0-9A-F]{8}-[0-9A-F]{4}-[0-9A-F]{4}-[0-9A-F]{4}-[0-9A-F]{12}[^@]*@
回答4:
^[^@]*([a-f0-9]{8}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{4}-[a-f0-9]{12})
will match the any hex in the 8-4-4-4-12 format that comes before a @
回答5:
there is also one way in a single line to get GUID
string findGuid = "hi Aether experiment 1481de3f-281e-9902-f98b-31e9e422431f @sdfsf 1481de3f-281e-9902-f98b-31e9e422431f"; //Initialize a new string value
var guids = Regex.Matches(Regex.Split(findGuid, "@")[0], @"(\{){0,1}[0-9a-fA-F]{8}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{4}\-[0-9a-fA-F]{12}(\}){0,1}")[0]; //Match all substrings in findGuid
来源：https://stackoverflow.com/questions/856327/regex-to-get-a-guid-from-a-email-reply