Compare data of 2 xml files and output the difference

问题

I have 2 xml files with same schema and I want to compare both the files to get only nodes which are present in 1st document but not in 2nd document and vise versa.

Case 1:

so my 1st xml is a.xml

<cases>
    <no sort="1">1</no>
    <no sort="2">2</no>
    <no sort="3">3</no>
    <no sort="4">4</no>
    <no sort="5">5</no>
    <no sort="6">6</no> 
</cases>

2nd xml is b.xml

<cases>
    <no sort="1">1</no>
    <no sort="2">2</no>
    <no sort="3">3</no>
    <no sort="4">4</no>
    <no sort="5">5</no>
    <no sort="6">6</no>
     <no sort="7">9</no>
 </cases>

Expected result after comparison should be

<cases>
       <no sort="7">9</no>
 </cases>

if <no sort="7">9</no> is in the a.xml and not in b.xml it should output the same result. So basically merging both document and remove nodes which are present in both documents.

I was thinking to loop through documents one by one and use xpath to check if the node is present is other document and if found discard it in the output. Any better solution to implement it in xslt 1.0 or xslt 2.0?

回答1:

How about this way (XSLT 1.0):

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="utf-8" indent="yes"/>

<xsl:variable name="file2" select="document('b.xml')" />

<xsl:variable name="IDs1" select="/cases/no/@sort" />
<xsl:variable name="IDs2" select="$file2/cases/no/@sort" />

<xsl:template match="/cases">
<cases>
    <xsl:apply-templates select="no[not(@sort=$IDs2)]"/>
    <xsl:apply-templates select="$file2/cases/no[not(@sort=$IDs1)]"/>
</cases>
</xsl:template>

<xsl:template match="no">
    <xsl:copy-of select="."/>
</xsl:template>

</xsl:stylesheet>

You need to apply the stylesheet to your "a.xml " file and make sure "b.xml " is in the same directory.

回答2:

If you websearch "xml diff", you'll find past versions of tools that compare XML documents and output their differences as an XML document See also https://stackoverflow.com/questions/1871076/are-there-any-free-xml-diff-merge-tools-available

回答3:

If I need to compare 2 XML files and see quickly the differences between them I sort the files using XSLT and then compare the two xml files manually by using WinMerge for example (a simple unix diff can also do the job). If you want to output the differences you can follow the method given by @keshlam

Here is the XSLT that sort my XML files :

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">

<xsl:output method="xml" indent="yes" encoding="UTF-8"/>

<xsl:template match="node()|@*">
    <xsl:copy>
            <xsl:apply-templates select="node()|@*">
                    <xsl:sort select="name()" />
                    <xsl:sort select="@*" />
                    <xsl:sort select="*" />
                    <xsl:sort select="text()" />
            </xsl:apply-templates>
    </xsl:copy>
</xsl:template>

</xsl:stylesheet>

来源：https://stackoverflow.com/questions/21466270/compare-data-of-2-xml-files-and-output-the-difference

标签

xslt

xslt-2.0