问题
I want to check if a field contains a string.
I want a function that would look like this:
FIND("string_to_find",field_to_search)
My data looks like this:
field_to_search
---------------
"no match in this string"
"record 2 has no matches"
"ahh finally xxxstring_to_findxxx is here"
I am looking for a function that identifies that the specified string is contained and at what position the string starts.
return
------
-1
-1
15
回答1:
The built in locate function does nearly exactly what you need except that for your input, it would return
return
------
0
0
16
Since it indexes from 1. So all you need to do is:
Select locate("string_to_find","ahh finally xxxstring_to_findxxx is here") -1; --returns 15
Select locate("string_to_find","foo") -1; --returns -1
回答2:
This is can be achieved by using instr and if in hive.
select if(instr(line,"xxxstring_to_findxxx")==0,-1,instr(line,"xxxstring_to_findxxx")) as position from find_tbl;
where line is your column name
来源：https://stackoverflow.com/questions/31926318/find-function-in-hive