How to print return value of method in Python?

问题

class Queue():
    def __init__(self):
        self.items = []

    def isEmpty(self):
        return self.items == []

    def Enqueue(self,item):
        return self.items.insert(0, item)

    def Size(self):
        return len(self.items)

    def Dequeue(self):
        return self.items.pop()

Q = Queue()    
def Hotpot(namelist,num):

    for name in namelist:
        Q.Enqueue(name)

    while Q.Size() > 1:
        for i in range(num):
           Q.Enqueue(Q.Dequeue())
        Q.Dequeue()
    return Q.Dequeue() # I would like to print and see what is getting removed, I tried with x = Q.Dequeue(), print x and print Q.Dequeue() but im getting "None"



print Hotpot(['A','B','C','D','E','F'],7)

Hi Team, I am trying above code for checking Queue, here I would like to print which value is removing each cycle. While printing I am getting none oly, please help me what changes I have to do for my expectation.

回答1:

If you want to know what's goingto be returned, you need to save it locally, print what you saved, then return what you saved. Something like:

    x = Q.Dequeue()
    print(x)
    return x

回答2:

Your code works for me, when you change Q.Dequeue() by print Q.Dequeue(). Better python would be:

from collections import deque

def hotspot(names, num):
    queue = deque(reversed(names))
    while len(queue)>1:
        queue.rotate(num)
        print queue.pop()
    return queue.pop()

print hotspot(['A','B','C','D','E','F'], 7)

来源：https://stackoverflow.com/questions/25153300/how-to-print-return-value-of-method-in-python