Passing and accessing parameters in XSLT

问题

I have an XML on which I am displaying the test cases as HTML using XSLT.

I have one query.

How to pass a variable as a parameter and access it on the other page.

So far I achieved this:

               <xsl:for-each select="//test-suite[@type='TestFixture']">
                <tr>      
                    <xsl:choose>
                    <xsl:when test="contains(@result, 'Success')">
                    <xsl:variable name="nameOfPage" select="@name" />
                <td><a href="DownloadManagerFeature.xml?nameOfPage={$nameOfPage}" style="text-decoration: none" ><font color="239625"><xsl:value-of select="@name"/></font></a></td>
                <td><xsl:value-of select="@result"/></td>
                <td><xsl:value-of select="@time"/></td>
                    </xsl:when>

As you can see, I am setting the value of name parameter to nameOfPage and I am passing it as a URL parameter.

But I am facing some issues retrieving it on other page.

 <td>test page</td>
 <td><xsl:value-of select="@nameOfPage"/></td>

The value is coming as null. I even added this at the top:

<xsl:variable name="nameOfPage" select="document('Mimedrive.Tests.xml')"/>

I am trying to match the nameOfPage to the @name in the case. When I do it with hardcoded values its working , like:

                </tr>
                <xsl:for-each select="//test-case">
                    <xsl:if test="contains(@name, 'XXX.DownloadManagerFeature')">
                <tr>
                <td><xsl:value-of select="@description"/></td>
                <td><xsl:value-of select="@result"/></td>
                </tr>

Please help.

回答1:

Use the JavaScript binding of XSLT to set the nameOfPage parameter before processing.

Assuming the XML document has the XHTML namespace as the default, then:

function transform()
  {
  var nameOfPage = var value=RegExp("nameOfPage[^&]+").exec(window.location.search)[0].replace(/[^=]+./,"");

  with (new XSLTProcessor)
     {
     setParameter(null, "nameOfPage", nameOfPage);
     importStylesheet("foo.xsl");
     transform.result = transformToFragment(this, document);
     transform.root = transform.result.xml;
     document.getElementById(appendTo).appendChild(transform.root);
     }
  }

Or use the processor specific processing instruction, as in Firefox:

<?xslt-param name="nameOfPage" value="foo"?>
<?xml-stylesheet type="text/xsl" href="foo.xsl"?>

Or use the processor specific setParameter method, for instance PHP:

$transformer  = new XSLTProcessor();
$transformer->importStylesheet("foo.xsl");
$transformer->setParameter('', 'nameOfPage', $_POST['nameOfPage']);

References

PI Parameters
Setting Parameters for XSLTProcessor
XSLTProcessor::setParameter
Saxon:Running a Transformation from the command line
Saxon:setParams
How to Write CGI Applications in Visual Basic

来源：https://stackoverflow.com/questions/23356113/passing-and-accessing-parameters-in-xslt

标签

xml

xslt

parameters