Truncate a string straight JavaScript

╄→гoц情女王★ 提交于 2019-11-27 03:04:33

Use the substring method:

var length = 3;
var myString = "ABCDEFG";
var myTruncatedString = myString.substring(0,length);
// The value of myTruncatedString is "ABC"

So in your case:

var length = 3;  // set to the number of characters you want to keep
var pathname = document.referrer;
var trimmedPathname = pathname.substring(0, Math.min(length,pathname.length));

document.getElementById("foo").innerHTML =
     "<a href='" + pathname +"'>" + trimmedPathname + "</a>"

yes, substring. You don't need to do a Math.min; substring with a longer index than the length of the string ends at the original length.

But!

document.getElementById("foo").innerHTML = "<a href='" + pathname +"'>" + pathname +"</a>"

This is a mistake. What if document.referrer had an apostrophe in? Or various other characters that have special meaning in HTML. In the worst case, attacker code in the referrer could inject JavaScript into your page, which is a XSS security hole.

Whilst it's possible to escape the characters in pathname manually to stop this happening, it's a bit of a pain. You're better off using DOM methods than fiddling with innerHTML strings.

if (document.referrer) {
    var trimmed= document.referrer.substring(0, 64);
    var link= document.createElement('a');
    link.href= document.referrer;
    link.appendChild(document.createTextNode(trimmed));
    document.getElementById('foo').appendChild(link);
}

Thought I would give Sugar.js a mention. It has a truncate method that is pretty smart.

From the documentation:

Truncates a string. Unless split is true, truncate will not split words up, and instead discard the word where the truncation occurred.

Example:

'just sittin on the dock of the bay'.truncate(20)

Output:

just sitting on...

Following code truncates a string and will not split words up, and instead discard the word where the truncation occurred. Totally based on Sugar.js source.

function truncateOnWord(str, limit) {
        var trimmable = '\u0009\u000A\u000B\u000C\u000D\u0020\u00A0\u1680\u180E\u2000\u2001\u2002\u2003\u2004\u2005\u2006\u2007\u2008\u2009\u200A\u202F\u205F\u2028\u2029\u3000\uFEFF';
        var reg = new RegExp('(?=[' + trimmable + '])');
        var words = str.split(reg);
        var count = 0;
        return words.filter(function(word) {
            count += word.length;
            return count <= limit;
        }).join('');
    }

Here's one method you can use. This is the answer for one of FreeCodeCamp Challenges:

function truncateString(str, num) {


if (str.length > num) {
return str.slice(0, num) + "...";}
 else {
 return str;}}

Yes, substring works great:

stringTruncate('Hello world', 5); //output "Hello..."
stringTruncate('Hello world', 20);//output "Hello world"

var stringTruncate = function(str, length){
  var dots = str.length > length ? '...' : '';
  return str.substring(0, length)+dots;
};

in case you want to truncate by word.

function limit(str, limit, end) {

      limit = (limit)? limit : 100;
      end = (end)? end : '...';
      str = str.split(' ');
      
      if (str.length > limit) {
        var cutTolimit = str.slice(0, limit);
        return cutTolimit.join(' ') + ' ' + end;
      }

      return str.join(' ');
    }

    var limit = limit('ILorem ipsum dolor sit amet, consectetur adipiscing elit. Vivamus metus magna, maximus a dictum et, hendrerit ac ligula. Vestibulum massa sapien, venenatis et massa vel, commodo elementum turpis. Nullam cursus, enim in semper luctus, odio turpis dictum lectus', 20);

    console.log(limit);
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!