How do I set params for WS.post() in play 2.1 Java

问题

I'm trying to perform a post with play.api.libs.ws.WS but I can't figure out how to set the params, my code:

Promise<Response> promise = WS.url(Play.application().configuration()
                .getString("sms.service.url")).post();

.post takes (T body, play.api.http.Writeable wrt, play.api.http.ContentTypeOf ct) but I don't understand how I should pass the params there. The documentation only states:

Promise<WS.Response> result = WS.url("http://localhost:9001").post("content");

How do I set the content eg. param1=foo and param2=bar?

回答1:

Try constructing the request like this:

WS.url("http://localhost:9001")
    .setQueryParameter("param1", "foo")
    .setQueryParameter("param2", "bar")
    .post("content");

The method url(java.lang.String url) returns a WS.WSRequestHolder reference which can be used to modify the original request using chained calls to setQueryParameter.

回答2:

Hmm I guess I should really start looking at the imports!

I accidentally used import play.api.libs.ws.WS instead of import play.libs.WS; When using play.libs.WS all the methods such as post(String string) and setContentType(String string) revealed themselves. This is how I did it:

import play.Play;
import play.libs.F;
import play.libs.WS;

public static Result wsAction() {
    return async(
        play.libs.WS.url(Play.application().configuration()
            .getString("sms.service.url"))
            .setContentType("application/x-www-form-urlencoded; charset=utf-8")                       
            .post("param1=foo&param2=bar").map(
                new F.Function<WS.Response, Result>() {
                    public Result apply(WS.Response response) {
                       return ok(response.toString());
                    }
                }
            )
        );
    }

回答3:

The accepted answer is wrong, or at least misleading. The code

WS.url("http://localhost:9001")
    .setQueryParameter("param1", "foo")
    .setQueryParameter("param2", "bar")
    .post("content");

will post the string content to http://localhost:9001/?param1=foo&param2=bar, which is almost certainly not what the OP wanted. What is much more likely to work is

WS.url("http://localhost:9001")
   .post(Map("param1" -> Seq("foo"),
             "param2" -> Seq("bar")))

which posts the form param1=foo&param2=bar to the the URL http://localhost:9001, which is typically what the server wants.

回答4:

WS.url(url)
.setContentType("application/x-www-form-urlencoded")
.post("param1=foo&param2=bar");

This method uses an HTTP POST method to send its form request. As seen from the official documentation of Play, you should had already known of the GET method.

这种方式是使用post方式提交表单请求，见于play的官方文档，get方式的你应该已经知道了。

回答5:

You need to pass in something that can be converted to serialized JSON. This works for me:

WS.url("https://www.someurl.com")
  .post(JsObject(Seq("theString" -> JsString(someString))))

The sequence takes any number of JsValues which can also be nested JsObjects.

回答6:

for me the best way

WS.url("http://localhost:9001")
.post(Json.toJson(ImmutableMap.of("param1", "foo", "param2", "bar")));

Map from http://docs.guava-libraries.googlecode.com/git-history/release/javadoc/com/google/common/collect/ImmutableMap.html

http://code.google.com/p/guava-libraries/wiki/ImmutableCollectionsExplained

回答7:

The right way of doing the blocking request in play 2.1 is

WSRequestHolder wsreqHolder = WS.url("<SOME URL WHICH TAKES PARAMETER>");
wsreqHolder.setQueryParameter("id", "100");
F.Promise<WS.Response> promiseOfResult = wsreqHolder.get();

WS.Response response = promiseOfResult.get(); //block here

String jsonData =  response.getBody();
return ok("Client:"+jsonData);

I have tried it. It works

来源：https://stackoverflow.com/questions/14937710/how-do-i-set-params-for-ws-post-in-play-2-1-java

标签

java

playframework-2.1