OrientDB: Efficient way to select records with a value equal to the max of all such values?

问题

I'm not sure how to do this without using a JOIN (which ODB doesn't have, of course). In "generic" SQL, you might do something like this:

Select * FROM table
INNER JOIN
  (SELECT max(field) AS max_of_field, key FROM table GROUP BY key) sub
ON table.field = sub.max_of_field AND table.key = sub.key

Is there an efficient way to do this in ODB, using SELECT and/or MATCH?

来源：https://stackoverflow.com/questions/49460138/orientdb-efficient-way-to-select-records-with-a-value-equal-to-the-max-of-all-s