How to store a 64 bit integer in two 32 bit integers in Ruby

问题

As the title says, I'm a little lost on how to accomplish this in Ruby...there are number of topics on how to do this in C or C++. Any ruby experts out there that can chime in on this?

回答1:

The same syntax you'd use in C works in ruby, just drop the typecasts:

n = 0xFFFFFFFFEEEEEEEE
x = (n & 0xFFFFFFFF00000000) >> 32
y =  n & 0xFFFFFFFF
puts x.to_s(16)
# => "ffffffff"
puts y.to_s(16)
# => "eeeeeeee"
v = x << 32 | y
puts v.to_s(16)
# => "ffffffffeeeeeeee"

If you need the values to be in chunks of exactly 32 bits (i.e. you need to speak binary to some external data file or program), then you'll want to use Array#pack and String#unpack to get the right bits.

回答2:

one 64bit integer is not equal to two 32bit integers.

http://en.wikipedia.org/wiki/Integer_(computer_science)

来源：https://stackoverflow.com/questions/4834424/how-to-store-a-64-bit-integer-in-two-32-bit-integers-in-ruby