Bash command to write the contents of multiple files into a single file

问题

I'm wondering what's the best way to combine multiple .html files (spread across many folders) into one single html file. If someone could create a simple bash command that would be fantastic. (This is a workaround so I can use firebug's command line API to effectively search an entire site for html selector combinations. As far as I know, firebug can only search on one page.)

Any help is greatly appreciated for this stymied front-end designer.

回答1:

cat file1.html file2.html file3.html > newfile.html

Edit This may be easier

find . -name="*.html" | xargs cat >> ../newfile.html

Note that newfile.html is pushed up from the current directory so it is not cat'ed into itself.

回答2:

Well, if you're not concerned about the resulting file being correct, cat seems like the easiest way to go:

cat file1.html file2.html file3.html > result.html

But of course each of those files with have an <html> tag at the top and a closing one at the bottom, so it won't be a valid HTML file. Firefox will probably load it, but I don't know how it will display it... perhaps only the first one?

回答3:

You cold always use grep to search something in a group of files instead of merging all of the files and then searching that one file.

grep <string you are looking for> <folder containing all of files> -r

回答4:

for file in `ls *.html`; do cat "$file" >> output.html; done

来源：https://stackoverflow.com/questions/640363/bash-command-to-write-the-contents-of-multiple-files-into-a-single-file

标签

bash

firebug