What is the inverse notion of “refinement”

最后都变了- 提交于 2019-12-11 04:08:00

问题


In the world of generic programing the notion of refinement is very common. In particular given a concept C1, then we say that a concept C2 refines C1 if it provides all the functionalities of C1 and possibly more.

How do you call the inverse relation? So if C2 is a refinement of C1 then C1 is a what of C2?


回答1:


Since the related transformation of requirements is called "lifting" I suggest the same for concepts. C1 is a lifting of C2. However someone with native English should better help here.




回答2:


There are two terms in linguistics which define the relation discussed in the topic.

Hyponym shares a type-of relationship with its hypernym.

Hypernymy is the semantic relation in which one word is the hypernym of another. Hyponymy is the oppopsite relation.

Then "bulldog" is a hyponym of the "dog" concept, the "dog" concept is the hypernym for the bulldog concept.



来源:https://stackoverflow.com/questions/16355303/what-is-the-inverse-notion-of-refinement

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