VBA - test if a value is a valid selection for a PivotField

二次信任 提交于 2019-12-11 03:47:14

问题


For a pivot table (pt1) on Sheet1, I use VBA to change the value of a filter field (filterfield) using the code below. Let's say values for field can be A, B or C

Sheets("Sheet1").PivotTables("pt1").PivotFields("filterfield").CurrentPage = "A"

Occasionally, and let's say randomonly for the purposes of this question, A, B or C will not be a valid selection for filterfield. When VBA attempts to change the field, it throws a run-time error. I want to avoid this.

How can I check if my values are valid for filterfield before I run the code above? I would like to avoid using On Error and VBA does not have try/catch functionality..


回答1:


You can iterate through the PivotItems and check the Name against your test.

Sub CheckIfPivotFieldContainsItem()

    Dim pt As PivotTable
    Set pt = Sheet1.PivotTables(1)

    Dim test_val As Variant
    test_val = "59"

    Dim pivot_item As PivotItem
    For Each pivot_item In pt.PivotFields("C").PivotItems
        If pivot_item.Name = test_val Then
            Debug.Print "MATCHES"
        End If
    Next pi

End Sub

Relevant data shows that a match should exist and indeed it returns MATCHES.




回答2:


If you want to have a helper function and do this without looping values you may use visual basic OnErrorResumeNext trick.

Private Function hasPivotItem(pField As PivotField, value As String) As Boolean
    On Error Resume Next
    hasPivotItem = Not IsNull(pField.PivotItems(value))
    On Error GoTo 0
End Function

' somewhere in your vba program
Debug.Print hasPivotItem(ptTable.PivotFields("Level"), "1")
Debug.Print hasPivotItem(ptTable.PivotFields("Level"), "-123")


来源:https://stackoverflow.com/questions/30578880/vba-test-if-a-value-is-a-valid-selection-for-a-pivotfield

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