Is lldb working with fortran?

≯℡__Kan透↙ 提交于 2019-12-11 03:44:36

问题


I am trying to breakpoint a fortran program with lldb on a Mac OS 10.12.5 system. I have

program badcall
      integer a,b
      a=2
      b=3

write(*,*) a, b
end

I (have to) compile with the intel compilers.

ifort -g badcall.f90 -o badcall

then I run with lldb and do

breakpoint set -f badcall.f90 -l 5

programs stops normally

Process 59474 stopped
* thread #1, queue = 'com.apple.main-thread', stop reason = breakpoint 1.1
    frame #0: 0x0000000100000f35 prova`MAIN__ at badcall.f90:6
   3          a=2
   4          b=3
   5          

However if I then try to print the variable b I get nothing

(lldb) p b
(lldb) print b
(lldb) q

So am I missing something? Is lldb really usable to debug fortran code?


回答1:


It seems that lldb doesn't support Fortran, yet :( You will have to go with gdb:

curl "http://ftp.gnu.org/gnu/gdb/gdb-8.0.tar.gz" -o gdb-8.0.tar.gz
tar zxf gdb-8.0.tar.gz
cd gdb-8.0
./configure
make

Make sure to Code Sign the gdb! Follow instructions here:

https://gcc.gnu.org/onlinedocs/gcc-4.8.1/gnat_ugn_unw/Codesigning-the-Debugger.html

and you should be good to go

gfortran -g -o fort_sample ./fort_sample.f90
gdb ./fort_sample
(gdb) list
1   program badcall
2         integer a,b
3         a=2
4         b=3
5
6   write(*,*) a, b
7   end
(gdb) break 6
Breakpoint 1 at 0x100000e0e: file ./fort_sample.f90, line 6.
(gdb) run
...
...
badcall () at ./fort_sample.f90:6
6   write(*,*) a, b
(gdb) print a
$1 = 2
(gdb) print b
$2 = 3
(gdb)


来源:https://stackoverflow.com/questions/44988718/is-lldb-working-with-fortran

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