VBA EXCEL Multiple Nested FOR Loops that Set two variable for expression

前提是你 提交于 2019-12-11 03:29:48

问题


Ok so I’ve done a good deal of searching found some and played and little. I cannot seem to get these loops to work fully I can get on part or another but not the whole. As is the first loop works fine then it goes wonky.

T is the destination for the expression output t.Value = time1 - time2
Y is a set time and date that does not change = time1
X is time and date and has to be extracted from the range in the same column as the corresponding y. x= time 2

I have uploaded the corresponding segment of my workbook

https://docs.google.com/open?id=0BzGnV1BGYQbvMERWU3VkdGFTQS1tYXpXcU1Mc3lmUQ

I have played with conditional exits rearranging the for loops. I even considered trying goto until I noticed the large pile of bodies created by its very mention.

I am open to and grateful for any advice or direction. I noticed a few languages have exit and continue options but it does not appear VB does?

Here is the loop I have I have stripped out the mess I made while trying to get it to work.

Sub stituterangers()
Dim dify As Boolean
Dim difx As Boolean
Dim time2 As Date
Dim time1 As Date

For Each t In range("d7:cv7")
       For Each x In range("d8:cv11")
             If x > 0 Then time2 = x           
           For Each y In range("d2:cv2")
            time1 = y                     
        t.Value = time1 - time2
        t = 0
                Next y
      Next x
Next t
End Sub 


Sub stituterangersNEW()
Dim t As range
Dim x As range
Dim dify As Boolean
Dim difx As Boolean
Dim time2 As Date
Dim time1 As Date

On Error Resume Next

    'Looping through each of our output cells.
    For Each t In range("d7:cv7")



     For Each y In range("d2:cv2")
            If t.Column = y.Column Then
            time1 = y.Value
             If y = 0 Then Exit Sub
                End If

        For Each x In range("d8:cv11")
            'Check to see if our dep time corresponds to
            'the matching column in our output
            If t.Column = x.Column Then

                If x > 0 Then
                    time2 = x.Value

                    t.Value = time1 - time2

                    Exit For
                End If
            End If


            Next x

        Next y
    Next t

End Sub

回答1:


I can't get to your google docs file at the moment but there are some issues with your code that I will try to address while answering

Sub stituterangersNEW()
Dim t As Range
Dim x As Range
Dim dify As Boolean
Dim difx As Boolean
Dim time2 As Date
Dim time1 As Date

    'You said time1 doesn't change, so I left it in a singe cell.
    'If that is not correct, you will have to play with this some more.
    time1 = Range("A6").Value

    'Looping through each of our output cells.
    For Each t In Range("B7:E9") 'Change these to match your real ranges.

        'Looping through each departure date/time.
        '(Only one row in your example. This can be adjusted if needed.)
        For Each x In Range("B2:E2") 'Change these to match your real ranges.
            'Check to see if our dep time corresponds to
            'the matching column in our output
            If t.Column = x.Column Then
                'If it does, then check to see what our time value is
                If x > 0 Then
                    time2 = x.Value
                    'Apply the change to the output cell.
                    t.Value = time1 - time2
                    'Exit out of this loop and move to the next output cell.
                    Exit For
                End If
            End If
            'If the columns don't match, or the x value is not a time
            'then we'll move to the next dep time (x)
        Next x
    Next t

End Sub

EDIT

I changed you worksheet to play with (see above for the new Sub). This probably does not suite your needs directly, but hopefully it will demonstrate the conept behind what I think you want to do. Please keep in mind that this code does not follow all the coding best preactices I would recommend (e.g. validating the time is actually a TIME and not some random other data type).

     A                      B                   C                   D                  E
1    LOAD_NUMBER            1                   2                   3                  4
2    DEPARTURE_TIME_DATE    11/12/2011 19:30    11/12/2011 19:30    11/12/2011 19:30    11/12/2011 20:00                
4    Dry_Refrig 7585.1  0   10099.8 16700
6    1/4/2012 19:30

Using the sub I got this output:

    A           B             C             D             E
7   Friday      1272:00:00    1272:00:00    1272:00:00    1271:30:00
8   Saturday    1272:00:00    1272:00:00    1272:00:00    1271:30:00
9   Thursday    1272:00:00    1272:00:00    1272:00:00    1271:30:00


来源:https://stackoverflow.com/questions/9690484/vba-excel-multiple-nested-for-loops-that-set-two-variable-for-expression

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