Sorting array of objects matching ids on a different set

问题

I have an array of objects

array = [
    {id: 5, name: "Helen", age: 20}, 
    {id: 15, name: "Lucy", age: 30}, 
    {id:7, name: "Carlos", age: 1}
]

Then I have a similar array sorted differently

arraySorted = [        
    {id: 15, name: "Lucy", age: 2}, 
    {id: 5, name: "Lara", age: 11}, 
    {id:7, name: "Carlos", age: 10}
]

The ids of the objects on both arrays will always match, the rest of the properties may or may not.

What I need is sorting the array in the same id order as arraySorted.

(it can be also done on plain JavaScript, lodash is not necessary but maybe it will be useful)

回答1:

Rather than sort, use map, find and Object.assign instead

arraySorted.map( s => Object.assign( s, array.find( t => t.id == s.id ) ) );

Demo

var array = [{
    id: 5,
    name: "Helen",
    age: 20
  },
  {
    id: 15,
    name: "Lucy",
    age: 30
  },
  {
    id: 7,
    name: "Carlos",
    age: 1
  }
];
var arraySorted = [{
    id: 15,
    name: "Lucy",
    age: 2
  },
  {
    id: 5,
    name: "Lara",
    age: 11
  },
  {
    id: 7,
    name: "Carlos",
    age: 10
  }
];
array = arraySorted.map(s => Object.assign(s, array.find(t => t.id == s.id)));

console.log(array);

回答2:

See Map and Array.prototype.map() for more info.

// Raw.
const raw = [
    {id: 5, name: "Helen", age: 20}, 
    {id: 15, name: "Lucy", age: 30}, 
    {id:7, name: "Carlos", age: 1}
]

// Sorted.
const sorted = [        
    {id: 15, name: "Lucy", age: 2}, 
    {id: 5, name: "Lara", age: 11}, 
    {id:7, name: "Carlos", age: 10}
]

// Match.
const match = (raw, sorted) => (m => sorted.map(s => m.get(s.id)))(new Map(raw.map(r => [r.id, r])))

// Output.
const output = match(raw, sorted)

// Proof.
console.log(output)

回答3:

The new array can be obtained via Array.prototype.map:

const newArray = arraySorted.map(sortedItem => 
  array.find(item => item.id === sortedItem.id)
)

console.log(newArray)

回答4:

You can use a Map, and avoid using nested iteration methods (like find, which make the solution have a worse time complexity), assuming that indeed you have all the same id values in both arrays:

const array = [{id: 5, name: "Helen", age: 20}, {id: 15, name: "Lucy", age: 30}, {id:7, name: "Carlos", age: 1}],
    arraySorted = [{id: 15, name: "Lucy", age: 2},{id: 5, name: "Lara", age: 11},{id:7, name: "Carlos", age: 10}]

const result = arraySorted.map((map => row => array[map.get(row.id)])
                               (new Map(array.map((row, i) => [row.id, i]))));

console.log(result);

回答5:

Try this, hope this helps

var array=[{id:5,name:"Helen",age:20},{id:15,name:"Lucy",age:30},{id:7,name:"Carlos",age:1}];

var arraySorted=[{id:15,name:"Lucy",age:2},{id:5,name:"Lara",age:11},{id:7,name:"Carlos",age:10}];

array = arraySorted.map(s => array.find(t => t.id == s.id));

console.log(array);

回答6:

You can use Map to sort your array:

let a1 = [{id: 5, name: "Helen", age: 20}, {id: 15, name: "Lucy", age: 30}, {id:7, name: "Carlos", age: 1}],
    a2 = [{id: 15, name: "Lucy", age: 2}, {id: 5, name: "Lara", age: 11}, {id:7, name: "Carlos", age: 10}];

let map = ((m) => (
             a2.forEach(({id}) => m.set(id, a1.find(o => o.id === id))), m
          ))(new Map());

let result = [...map.values()];

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

来源：https://stackoverflow.com/questions/49528252/sorting-array-of-objects-matching-ids-on-a-different-set

标签

javascript

arrays

sorting

lodash