问题
Situation: My Python script has a line of code that copies itself to another directory
shutil.copyfile(os.path.abspath(__file__), newPath)
Problem: The script is then compiled into an EXE and ran. The error given is as follows:
FileNotFoundError: No such file or Directory: "C:\Path\To\EXE\script.py"
As you can see, the EXE is looking for the .py version of itself (i.e. uncompiled version)
Question: Is there another Python command that can still let the executable find itself and not the .py version of itself?
Additional information: I was going to try to just replace .py with .exe and see if it works -- it would have if not for the program to fail if I change the name of the executable.
C:\ > script.exe
#Works as expected
C:\ > ren script.exe program.exe
C:\ > program.exe
FileNotFoundError: No such file or directory: "C:\script.py"
回答1:
I was stuck in this problem too. Finally I found the solution from the official document.
Solution:
Use sys.argv[0] or sys.executable to access the real path of the executed file.
Explanation:
This is because your executable is a bundle environment. In this environment, all the __file__ constants are relative paths relative to a virtual directory (actually the directory where the initial entrance file lies in).
As instructed by the document, you can access the absolute by using sys.argv[0] or sys.executable, as they are pointing to the actually executed command. So in a bundle environment, you call script.exe, and sys.executable will be script.exe. While in a running live environment, you call python script.path, and sys.executable will be python.exe.
回答2:
Try the following:
from os.path import abspath, splitext
fromfile_without_ext, ext = splitext(abspath(__file__))
shutil.copyfile(fromfile_without_ext + '.exe', newPath)
(Did not test it, but should work...)
来源：https://stackoverflow.com/questions/50959340/pyinstaller-exes-file-refers-to-a-py-file