How to get more than 20 results from a user timeline using processing and Twitter4j?

问题

I'm trying to make a sketch that gets the last 100 tweets from a specific user's twitter timeline. I'm using Twitter4j and the sketch works fine but I've learned that Twitter4J by default limits the timeline results to 20.

I've seen this page to learn about getting more than 100 when using Queries, but it seems to be working differently when trying to get a specific user's timeline. How to retrieve more than 100 results using Twitter4j

Thanks for looking!

Here is my sketch:

import twitter4j.conf.*;
import twitter4j.internal.async.*;
import twitter4j.internal.org.json.*;
import twitter4j.internal.logging.*;
import twitter4j.json.*;
import twitter4j.internal.util.*;
import twitter4j.management.*;
import twitter4j.auth.*;
import twitter4j.api.*;
import twitter4j.util.*;
import twitter4j.internal.http.*;
import twitter4j.*;
import twitter4j.internal.json.*;


ConfigurationBuilder cb = new ConfigurationBuilder();

cb.setOAuthConsumerKey("XXXXXX");
cb.setOAuthConsumerSecret("XXXXXX");
cb.setOAuthAccessToken("XXXXXX");
cb.setOAuthAccessTokenSecret("XXXXXX");

java.util.List statuses = null;

Twitter twitter = new TwitterFactory(cb.build()).getInstance();

String userName ="XXXXXX";
int numTweets = 100;
String[] twArray = new String[numTweets];



  try {
    statuses = twitter.getUserTimeline(userName);
  }
  catch(TwitterException e) {
  }

  for (int i=0; i<statuses.size(); i++) {
    Status status = (Status)statuses.get(i);

    //println(status.getUser().getName() + ": " + status.getText());
    twArray[i] = status.getUser().getName() + ": " + status.getText();

  }


println(twArray);

回答1:

How about something like this?

Paging pg = new Paging();
String userName = "uzr";
void setup() {

  ConfigurationBuilder cb = new ConfigurationBuilder();
  cb.setOAuthConsumerKey("xxxx");
  cb.setOAuthConsumerSecret("xxxx");
  cb.setOAuthAccessToken("xxxx");
  cb.setOAuthAccessTokenSecret("xxxx");

  Twitter twitter = new TwitterFactory(cb.build()).getInstance();
  int numberOfTweets = 100;
  long lastID = Long.MAX_VALUE;
  ArrayList<Status> tweets = new ArrayList<Status>();
  while (tweets.size () < numberOfTweets) {
    try {
      tweets.addAll(twitter.getUserTimeline(userName,pg));
      println("Gathered " + tweets.size() + " tweets");
      for (Status t: tweets) 
        if(t.getId() < lastID) lastID = t.getId();
    }
    catch (TwitterException te) {
      println("Couldn't connect: " + te);
    }; 
    pg.setMaxId(lastID-1);
  }
}

回答2:

I know the question is old, but the accepted answer is not the best solution for this, below is a more elegant piece of code to solve this problem.

...

Paging p = new Paging();
p.setCount(100);
return twitter.getUserTimeline("screenName",p);

来源：https://stackoverflow.com/questions/19224653/how-to-get-more-than-20-results-from-a-user-timeline-using-processing-and-twitte

标签

limit

processing

twitter4j

timeline