问题
SQL is not my strong suit, but I cannot figure out why this isn't working. I simply want to run a different AND statement based on a value. Specifically, I want to change the datePart in the dateDiff function if foo is = 0
SELECT foo,
bar,
test
FROM table
WHERE bar = 1,
CASE WHEN foo = 0
AND dateDiff(dd, getDate(), 2 ) < test
ELSE
AND dateDiff(hh, getDate(), 2 ) < test
END
回答1:
Try this one -
SELECT foo,
bar,
test
FROM [table]
WHERE bar = 1
AND (
(
foo = 0
AND
DATEDIFF(dd, GETDATE(), 2 ) < test
)
OR
DATEDIFF(hh, GETDATE(), 2 ) < test
)
回答2:
You can try like this
SELECT foo,
bar,
test
FROM table
WHERE bar = 1 And
(CASE WHEN foo = 0
then dateDiff(dd, getDate(), 2 )
ELSE
dateDiff(hh, getDate(), 2 )
END)<test
回答3:
If I had to guess at what you're actually aiming for, it's that you wanted to subtract 2 hours or days from GETDATE() for use in your comparison.
Here's what I think you're aiming for:
SELECT foo,
bar,
test
FROM table
WHERE bar = 1 AND
(
(foo = 0 AND DATEADD(day,-2, GETDATE()) < test)
OR
(foo<>0 AND DATEADD(hour,-2,GETDATE()) < test)
)
I can't think that you really intended those DATEDIFF calls. For example, today (3rd July 2013), this expression:
select CAST(DATEDIFF(dd,getdate(),2) as datetime)
Produces 1786-07-031. I'm assuming that test is a datetime and that the implicit conversion is being performed. Even if it's not, the numerical value of DATEDIFF(dd,getdate(),2) will always be a large negative number (unless or until it's run on a machine where GETDATE() returns a value from before the 20th Century)
1 Weirdly, I think 3rd July is the only day of the year on which the result will have the same month and day number.
来源:https://stackoverflow.com/questions/17441179/sql-server-2012-case-statement-in-where-clause