问题
Hi I did get how the Counting Semaphore works? Please help me in understanding.
As per my understanding if we set count as 3, then process can use 3 threads to access the resource. so, here just 3 threads have access on the resource. When 1 thread leaves the other waiting thread comes in. If my understanding is correct, these 3 thread can corrupt shared data too. Then what is use of it?
回答1:
Your observations are correct; typically a resource either needs to be restricted to one thread (e.g. it is being written to), or is safe to use with an unlimited number of threads (e.g. it is read-only). Restricting a resource to be used by say 5 threads is rarely useful.
Thus a counting semaphore with count N is most often used to restrict access to a pool of N resources...when the count reaches zero the next thread has to wait to obtain a resource from the pool.
However, I don't commonly find this useful in practice because simply controlling the number of threads accessing a pool of resources isn't sufficient, you need to manage the resources themselves as well. So I typically end up with a blocking queue containing the managed resources that threads can take from. When a thread is done with a resource, it returns that resource (e.g. an object) to the queue so that a waiting thread can take it.
The queue might internally use a semaphore to control access to the internal buffer, but that is usually encapsulated from the user of the queue.
See also
- Wikipedia: Semaphore - Important Observations
来源：https://stackoverflow.com/questions/9242539/what-is-counting-semaphore