问题
Following on from this question, which provides a solution but doesn't explain it (unfortunately, the links in the answers are now dead):
Take the following method:
void method(Map<?, ?> myMap) {
Set<Map.Entry<?, ?>> set = myMap.entrySet();
...
}
Simple, no? However, this fails to compile on jdk1.7.0_25:
incompatible types required: java.util.Set<java.util.Map.Entry<?,?>> found: java.util.Set<java.util.Map.Entry<capture#1 of ?,capture#2 of ?>>
WTF? Map.entrySet() is specified as returning an object of type Set<Map.Entry<K, V>>, so in the example above, myMap.entrySet() returns a Set<Map.Entry<?, ?>>. But it doesn't compile!
Even weirder, from the linked question at the top, changing the method to this makes it compile:
void method(Map<?, ?> myMap) {
Set<? extends Map.Entry<?, ?>> set = myMap.entrySet();
...
}
WTF??? Calling entrySet on a Map<?, ?> returns a Set<Map.Entry<K, V>>, which can't be assigned to a variable of type Set<Map.Entry<K, V>>, but it can to a variable of type Set<? extends Map.Entry<K, V>>?????
Can anyone shed light on what's going on here? And does this mean that, whenever I write a method using a wildcard type at least 2 levels deep, I have to remember to make it ? extends ... somewhere?
回答1:
Each of those ? can vary independently, so there's no guarantee that the <?,?> in the declaration of myMap matches the <?,?> in the declaration of set.
What this means is that once I have a Set<Map<?,?>>, I can put any type of Map into that set, because Map<?,?> is a supertype of all types of Map. But this is not a property that Set<Map<String,Integer>> (for example) has - it's far more restrictive in terms of what types of map I can put into it. So Set<Map<?,?>> is not a supertype of Set<Map<String,Integer>>. But myMap.entrySet() could easily be a Set<Map<String,Integer>>, depending on what myMap is. So the compiler has to forbid us from assigning it to a variable of type Set<Map<?,?>>, and that's what's happening.
On the other hand, Set<? extends Map<?,?>> is a supertype of Set<Map<String,Integer>>, because Map<String,Integer> is a subtype of Map<?,?>. So it's OK to assign myMap.entrySet() to a variable of type Set<? extends Map<?,?>>.
Note that there's nothing special about String and Integer here, but myMap has to be a map of something!
You could write
<K, V> void method(Map<K, V> myMap) {
Set<Map.Entry<K, V>> set = myMap.entrySet();
...
来源：https://stackoverflow.com/questions/19727396/incompatible-wildcard-types-that-should-be-compatible