Property 'next' does not exist on type 'Observable<{}>'

问题

trying to do the following

let o = new Observable() ;
o.delay( 3000 ).next( { stuff } ) ;

Getting the following error

[ts] Property 'next' does not exist on type 'Observable<{}>'

also tried

Let o = new Subject(); 
o.delay( 3000 ).next( { stuff } ) ;

Still getting

[ts] Property 'next' does not exist on type 'Observable<{}>'.

回答1:

You need to call next on the Subject instance. The o variable from your example is then the Subject chained with the operator that returns an Observable.

const s = new Subject(); 
const o = s.delay(3000);

o.subscribe(...);

s.next();

来源：https://stackoverflow.com/questions/49401761/property-next-does-not-exist-on-type-observable