API to determine whether running on iPhone or iPad [duplicate]

冷暖自知 提交于 2019-11-27 02:07:34
Andiih

Checkout UI_USER_INTERFACE_IDIOM.

Returns the interface idiom supported by the current device.

Return Value
UIUserInterfaceIdiomPhone if the device is an iPhone or iPod touch or UIUserInterfaceIdiomPad if the device is an iPad.

UIUserInterfaceIdiom

The type of interface that should be used on the current device

typedef enum {
   UIUserInterfaceIdiomPhone,
   UIUserInterfaceIdiomPad,
} UIUserInterfaceIdiom;
Dan Rosenstark

Just for my reference:

@property (nonatomic, readonly) BOOL isPhone;

-(BOOL)isPhone {
    return (UI_USER_INTERFACE_IDIOM()==UIUserInterfaceIdiomPhone);
}

or use a #define

#define IS_PHONE  (UI_USER_INTERFACE_IDIOM()==UIUserInterfaceIdiomPhone)

However, if you're using isPhone all over your code, that's generally bad practice. Use the factory pattern and polymorphism to keep your if statements contained, so you get objects created for phone or for iPad and then work with those.

Added

I'm using this solution all over my code now. It adds a standard factory pattern into the alloc.

#define ALLOC_PER_DEVICE()  id retVal = nil; \
                        NSString *className = NSStringFromClass(self);\
                        if (IS_PHONE && ![className hasSuffix:@"Phone"]) {\
                            className = [NSString stringWithFormat:@"%@Phone", className];\
                            Class newClass = NSClassFromString(className);\
                            retVal = [newClass alloc];\
                        }\
                        if (!retVal)\
                            retVal = [super alloc];\
                        assert(retVal != nil);\
                        return retVal\

Then my allocs look like this:

+alloc { ALLOC_PER_DEVICE(); }

And I add a subclass called TheClassPhone for the phone version.

Note: Since there's no multiple inheritance in Objective-C, using inheritance to solve your problems is a bit overrated (i.e., it doesn't work if you have subclasses of subclasses). Nothing like a good if when you need it.

  1. Check for the presence of the userInterfaceIdiom property, usings respondsToSelector:. If it doesn't exist, we are on a pre-3.2 device, thus not an iPad.
  2. If userInterfaceIdiom exists, use it.

Edit: ... which is obviously exactly what the UI_USER_INTERFACE_IDIOM() macro does, so use that instead. :)

You can check if you run the app on iPhone or iPad by using the following code:

- (NSString *)deviceModel
{
    struct utsname systemInfo;
    uname(&systemInfo);
    return [NSString stringWithCString:systemInfo.machine encoding:NSUTF8StringEncoding];
}

- (NSString *) platformString
{
    NSString *platform = [self deviceModel];
    if ([platform isEqualToString:@"iPhone1,1"])    return @"iPhone_2G";
    else if ([platform isEqualToString:@"iPhone1,2"])    return @"iPhone_3G";
    else if ([platform isEqualToString:@"iPhone2,1"])    return @"iPhone_3GS";
    else if ([platform isEqualToString:@"iPhone3,1"])    return @"iPhone_4";
    else if ([platform isEqualToString:@"iPhone3,3"])    return @"Verizon_iPhone_4";
    else if ([platform isEqualToString:@"iPhone4,1"])    return @"iPhone_4S";
    else if ([platform isEqualToString:@"iPhone5,1"])    return @"iPhone_5";
    else if ([platform isEqualToString:@"iPhone5,2"])    return @"iPhone_5";
    else if ([platform isEqualToString:@"iPod1,1"])      return @"iPod_Touch 1G";
    else if ([platform isEqualToString:@"iPod2,1"])      return @"iPod_Touch 2G";
    else if ([platform isEqualToString:@"iPod3,1"])      return @"iPod_Touch 3G";
    else if ([platform isEqualToString:@"iPod4,1"])      return @"iPod_Touch 4G";
    else if ([platform isEqualToString:@"iPad1,1"])           return @"iPad_1G";
    else if ([platform isEqualToString:@"iPad2,1"])      return @"iPad_2(WiFi)";
    else if ([platform isEqualToString:@"iPad2,2"])      return @"iPad_2(GSM)";
    else if ([platform isEqualToString:@"iPad2,3"])      return @"iPad_2(CDMA)";
    else if ([platform isEqualToString:@"iPad3,1"])      return @"iPad_3";
    else if ([platform isEqualToString:@"iPad3,2"])      return @"iPad_3(GSM/CDMA)";
    else if ([platform isEqualToString:@"iPad3,3"])      return @"iPad_3(GSM)";
    else if ([platform isEqualToString:@"iPad3,4"])      return @"iPad_3(GSM)";
    else if ([platform isEqualToString:@"iPad2,5"])      return @"iPad_mini_1G";
    else if ([platform isEqualToString:@"i386"])         return @"Simulator";
    else if ([platform isEqualToString:@"x86_64"])       return @"Simulator";
    return platform;
}
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