问题
When the function requires a char*, can you pass in a shared_ptr?
I'm reading in a whole text file (length = 100), and want to store the char's into a char[] array. The naive way I used was this:
ifstream dictFile(fileName);
size_t fileLength = 100;
char* readInBuffer(new char[fileLength]);
dictFile.read(readInBuffer, fileLength);
//processing readInBuffuer..............
delete[] readInBuffer;
dictFile.close();
Of course there is memory leak if an exception is thrown before the delete[] statement. I'm wondering if I can use shared_ptr readInBuffer(new char[fileLength]); But the function prototype
read ( char* s, streamsize n )
won't accept a smart pointer as input? Any tricks?
Edit: I'm trying to write something like this:
shared_ptr<char[]> readInBuffer(new char[fileLength]);
dictFile.read(readInBuffer.get(), fileLength);
But it won't compile.
回答1:
BIG FAT WARNING: creating a shared_ptr that points to an array provokes undefined behaviour, because the smart pointer will delete the pointer, not delete[] it. Use a vector instead!
Leaving this here because it might serve as a useful warning. Original answer follows...
The get() function returns the underlying raw pointer. You already wrote this in your code!
shared_ptr<char> readInBuffer(new char[fileLength]);
dictFile.read(readInBuffer.get(), fileLength);
The same result can be achieved with &*readInBuffer.
Of course, you have to be certain that dictFile.read() doesn't delete the pointer, or demons might fly out of your nose.
回答2:
Rather than using a pointer, you can use a vector instead.
std::vector<char> readInBuffer(fileLength);
dictFile.read(&readInBuffer[0], fileLength);
回答3:
No, you can't pass a shared_ptr. But you can create one, and call its get() member function to get a copy of the raw pointer to pass to the function. However, a shared_ptr doesn't deal with arrays; that's what vector is for. But you can use a unique_ptr to an array to manage that object:
std::unique_ptr<char[], std::default_delete<char[]> ptr(new char[whatever]);
f(ptr.get());
There may be a shorter way to write that first line, but I don't have time to dig it out.
来源：https://stackoverflow.com/questions/13405124/shared-ptr-for-a-raw-pointer-argument