问题
I use a population count (hamming weight) function intensively in a windows c application and have to optimize it as much as possible in order to boost performance. More than half the cases where I use the function I only need to know the value to a maximum of 15. The software will run on a wide range of processors, both old and new. I already make use of the POPCNT instruction when Intel's SSE4.2 or AMD's SSE4a is present, but would like to optimize the software implementation (used as a fall back if no SSE4 is present) as much as possible.
Currently I have the following software implementation of the function for 64bit (platform) mode:
int population_count64(unsigned __int64 w) {
w -= (w >> 1) & 0x5555555555555555ULL;
w = (w & 0x3333333333333333ULL) + ((w >> 2) & 0x3333333333333333ULL);
w = (w + (w >> 4)) & 0x0f0f0f0f0f0f0f0fULL;
return int((w * 0x0101010101010101ULL) >> 56);
}
So to summarize:
(1) I would like to know if it is possible to optimize this for the case when I only want to know the value to a maximum of 15.
(2) Is there a faster software implementation (for both Intel and AMD CPU's) than the function above (for unsigned 64bit integers)?
回答1:
It is indeed possible to optimise your function for the "maximum 15" case. The following shaves off a few operations:
inline int population_count64_max15(unsigned __int64 w)
{
w -= (w >> 1) & 0x5555555555555555ULL;
w = (w & 0x3333333333333333ULL) + ((w >> 2) & 0x3333333333333333ULL);
return int((w * 0x1111111111111111ULL) >> 60);
}
Inlining the function (using the inline keyword as above) should also increase performance.
回答2:
If you're on a 32-bit machine, split w into two 32-bit words, calculate the popcount separately for each half, then add up. This will get rid of some unneeded operations that are required to synthesize 64-bit operations from 32-bit ones (shifts, mults...). This also allows for increased parallelism if you interleave the calculations.
If you're compiling 64-bit code, you may try this:
int popcnt64(uint64_t w)
{
uint64_t w1 = (w & 0x2222222222222222) + ((w+w) & 0x2222222222222222);
uint64_t w2 = (w >> 1 & 0x2222222222222222) + (w >> 2 & 0x2222222222222222);
w1 = w1 + (w1 >> 4) & 0x0f0f0f0f0f0f0f0f;
w2 = w2 + (w2 >> 4) & 0x0f0f0f0f0f0f0f0f;
return (w1 + w2) * 0x0101010101010101 >> 57;
}
This contains more operations, but gives more opportunities of parallel execution to the CPU. On newer CPUs it should be slightly faster, on others it will be slightly slower.
来源:https://stackoverflow.com/questions/2960434/c-population-count-of-unsigned-64-bit-integer-with-a-maximum-value-of-15