How do I use % character in NSString stringWithFormat

问题

How do I use the % character literal in an NSString stringWithFormat?

I am trying to do: [NSString stringWithFormat:@"%%@,%@",string1,string2];

The first % does not show up.

回答1:

[NSString stringWithFormat:@"%%%@,%@",string1,string2];

回答2:

Two percent charicters, %%, will print as one %.

From the String Format Specifiers list.

回答3:

Try this:

   [NSString stringWithFormat:@"%@%%",str1];

回答4:

Using % two times (as escape character) should give you what you need. An example printing %foo,bar would look like this

[NSString stringWithFormat:@"%%%@,%@", @"foo", @"bar"];

来源：https://stackoverflow.com/questions/9949908/how-do-i-use-character-in-nsstring-stringwithformat