Show/hide div's with javascript on a button press (and have all div's hidden first)

问题

I am new to javascript and I cant seam to hide the div's to start with, I can get the divs to switch between each other any help would be great

<script type="text/javascript">
function show(elementId) { 
 document.getElementById("id1").style.display="none";
 document.getElementById("id2").style.display="none";
 document.getElementById("id3").style.display="none";
 document.getElementById(elementId).style.display="block";
}
</script>


<button type="button" onclick="show('id1');">Button 1</button>
<button type="button" onclick="show('id2');">Button 2</button>
<button type="button" onclick="show('id3');">Button 3</button>

<div id="id1">text 1</div>
<div id="id2">text 2</div>
<div id="id3">text 3</div>

回答1:

You can hide all the divs by adding inline styles:

<script type="text/javascript">
function show(elementId) { 
 document.getElementById("id1").style.display="none";
 document.getElementById("id2").style.display="none";
 document.getElementById("id3").style.display="none";
 document.getElementById(elementId).style.display="block";
}
</script>


<button type="button" onclick="show('id1');">Button 1</button>
<button type="button" onclick="show('id2');">Button 2</button>
<button type="button" onclick="show('id3');">Button 3</button>

<div id="id1"  style="display:none">text 1</div>
<div id="id2"  style="display:none">text 2</div>
<div id="id3"  style="display:none">text 3</div>

See it working here: http://jsbin.com/suhok/2/

回答2:

<script type="text/javascript">
function show(elementId) { 
 document.getElementById("id1").style.display="none";
 document.getElementById("id2").style.display="none";
 document.getElementById("id3").style.display="none";
 document.getElementById(elementId).style.display="block";
}
</script>
<style>
 div{
  display:none;
 }
</style>

<button type="button" onclick="show('id1');">Button 1</button>
<button type="button" onclick="show('id2');">Button 2</button>
<button type="button" onclick="show('id3');">Button 3</button>

<div id="id1">text 1</div>
<div id="id2">text 2</div>
<div id="id3">text 3</div>

All the div's will be hidden on the first go, you code will work this way, put buttons and div's under <body> tag and <script> and <style> under <head> tag

here is JSFindle Link

回答3:

I would use both CSS and JavaScript to accomplish this: http://jsfiddle.net/maximgladkov/XaMzB/1/

JavaScript

window.show = function(elementId) { 
    var elements = document.getElementsByTagName("div");
    for (var i = 0; i < elements.length; i++)
        elements[i].className = "hidden";

    document.getElementById(elementId).className = "";
}

CSS

.hidden {
    display: none;
}

HTML

<button type="button" onclick="show('id1');">Button 1</button>
<button type="button" onclick="show('id2');">Button 2</button>
<button type="button" onclick="show('id3');">Button 3</button>

<div id="id1">text 1</div>
<div id="id2" class="hidden">text 2</div>
<div id="id3" class="hidden">text 3</div>

回答4:

You can use pure CSS to hide the divs to begin with:

#id1, #id2 #id3 {
 display: none;
}

回答5:

Your code's fine. You just need to put the script block after everything else.

DEMO

<button type="button" onclick="show('id1');">Button 1</button>
<button type="button" onclick="show('id2');">Button 2</button>
<button type="button" onclick="show('id3');">Button 3</button>
<div id="id1">text 1</div>
<div id="id2">text 2</div>
<div id="id3">text 3</div>
<script type="text/javascript">
    function show(elementId) {
        document.getElementById("id1").style.display = "none";
        document.getElementById("id2").style.display = "none";
        document.getElementById("id3").style.display = "none";
        document.getElementById(elementId).style.display = "block";
    }
</script>

回答6:

<script type="text/javascript">
function hideAll(){
     document.getElementById("id1").style.display="none";
     document.getElementById("id2").style.display="none";
     document.getElementById("id3").style.display="none";    
}
function show(elementId) { 
    hideAll();
    document.getElementById(elementId).style.display="block";
}
</script>


<button type="button" onclick="show('id1');">Button 1</button>
<button type="button" onclick="show('id2');">Button 2</button>
<button type="button" onclick="show('id3');">Button 3</button>

<div id="id1">text 1</div>
<div id="id2">text 2</div>
<div id="id3">text 3</div>

<script type="text/javascript">
    hideAll();
</script>

jsfiddle: http://jsfiddle.net/y7YKV/

回答7:

Declare show method globally. See the fiddle. I think that's what you needed.

window.show= function(elementId) { 
 document.getElementById("id1").style.display="none";
 document.getElementById("id2").style.display="none";
 document.getElementById("id3").style.display="none";
 document.getElementById(elementId).style.display="block";
}

JSFiddle

来源：https://stackoverflow.com/questions/21730782/show-hide-divs-with-javascript-on-a-button-press-and-have-all-divs-hidden-fir

标签

javascript

html

hide

show