问题
I read from Effective Java that In the absence of synchronization the following sequence A below can be converted into sequence B by the virtual machine and this is called hoisting
. I also read somewhere that if variables are not declared as volatile instructions involving the variables can be reordered . Are hoisting and reordering the same thing?
while (!done) sequence A
i++;
if (!done)
while (true) sequence B
i++;
回答1:
They are slightly different.
Hoisting means that you have pulled some operation out of a loop because the loop itself does not affect the result of the operation. In your case, you are hoisting the conditional test out of the while loop.
Re-ordering means changing the sequence of instructions in a way that does not affect the result. Typically this would be adjacent instructions with no data dependencies, e.g. it does not matter which order you perform the following two statements:
int a = x;
int b = y;
回答2:
The term "reordering" as it's used in the Java Memory Model refers to all possible optimizations that may affect correctness of improperly synchronized programs.
So, reordering in this sense is a generic term that includes optimizations such as hoisting, effects of out-of-order execution, inconsistencies caused by memory hierarchy (i.e. caches), and so on.
回答3:
Reordering relates to performance of execution where as reordering doesn't impact performance.
Hoisting is done to reordering of Memory barrier instructions.
来源:https://stackoverflow.com/questions/11430095/are-hoisting-and-reordering-the-same-thing