问题
How can we remove a particular permission for all using os.chmod ?
In short, how can we write the below using os.chmod
chmod a-x filename
I do know that we can add permission to an existing one and remove also.
In [1]: import os, stat
In [5]: os.chmod(file, os.stat(file).st_mode | stat.S_IRGRP) # Make file group readable.
But I am not able to figure out the doing the all operation
回答1:
Cool. So the secret is you first need to get the current permissions. This is a bit of a mess, but it works.
current = stat.S_IMODE(os.lstat("x").st_mode)
The idea is that lstat.st_mode gives you the flags, but you need to crop that to the range that chmod accepts:
help(stat.S_IMODE)
#>>> Help on built-in function S_IMODE in module _stat:
#>>>
#>>> S_IMODE(...)
#>>> Return the portion of the file's mode that can be set by os.chmod().
#>>>
Then you can remove the stat.S_IEXEC flag with some bit operations, and this gives you the new number to use:
os.chmod("x", current & ~stat.S_IEXEC)
If you're not familiar with bit twiddling, & takes only those bits that both numbers have, and ~ inverts the bits of a number. so x & ~y takes those bits that x has and that y doesn't have.
回答2:
If you want to use os.chmod() then you can use below code:
import os
for dir_path, dir_names, files in os.walk('.'):
for file in files:
abs_path = os.path.join(dirpath, file)
os.chmod(abs_path, 0o755)
来源:https://stackoverflow.com/questions/25988471/remove-particular-permission-using-os-chmod