问题
I am trying to understand python's class inheritance methods and I have some troubles figuring out how to do the following:
How can I inherit a method from a class conditional on the child's input?
I have tried the following code below without much success.
class A(object):
def __init__(self, path):
self.path = path
def something(self):
print("Function %s" % self.path)
class B(object):
def __init__(self, path):
self.path = path
self.c = 'something'
def something(self):
print('%s function with %s' % (self.path, self.c))
class C(A, B):
def __init__(self, path):
# super(C, self).__init__(path)
if path=='A':
A.__init__(self, path)
if path=='B':
B.__init__(self, path)
print('class: %s' % self.path)
if __name__ == '__main__':
C('A')
out = C('B')
out.something()
I get the following output:
class: A
class: B
Function B
While I would like to see:
class: A
class: B
B function with something
I guess the reason why A.something() is used (instead of B.something()) has to do with the python's MRO.
回答1:
Calling __init__ on either parent class does not change the inheritance structure of your classes, no. You are only changing what initialiser method is run in addition to C.__init__ when an instance is created. C inherits from both A and B, and all methods of B are shadowed by those on A due to the order of inheritance.
If you need to alter class inheritance based on a value in the constructor, create two separate classes, with different structures. Then provide a different callable as the API to create an instance:
class CA(A):
# just inherit __init__, no need to override
class CB(B):
# just inherit __init__, no need to override
def C(path):
# create an instance of a class based on the value of path
class_map = {'A': CA, 'B': CB}
return class_map[path](path)
The user of your API still has name C() to call; C('A') produces an instance of a different class from C('B'), but they both implement the same interface so this doesn't matter to the caller.
If you have to have a common 'C' class to use in isinstance() or issubclass() tests, you could mix one in, and use the __new__ method to override what subclass is returned:
class C:
def __new__(cls, path):
if cls is not C:
# for inherited classes, not C itself
return super().__new__(cls)
class_map = {'A': CA, 'B': CB}
cls = class_map[path]
# this is a subclass of C, so __init__ will be called on it
return cls.__new__(cls, path)
class CA(C, A):
# just inherit __init__, no need to override
pass
class CB(C, B):
# just inherit __init__, no need to override
pass
__new__ is called to construct the new instance object; if the __new__ method returns an instance of the class (or a subclass thereof) then __init__ will automatically be called on that new instance object. This is why C.__new__() returns the result of CA.__new__() or CB.__new__(); __init__ is going to be called for you.
Demo of the latter:
>>> C('A').something()
Function A
>>> C('B').something()
B function with something
>>> isinstance(C('A'), C)
True
>>> isinstance(C('B'), C)
True
>>> isinstance(C('A'), A)
True
>>> isinstance(C('A'), B)
False
If neither of these options are workable for your specific usecase, you'd have to add more routing in a new somemethod() implementation on C, which then calls either A.something(self) or B.something(self) based on self.path. This becomes cumbersome really quickly when you have to do this for every single method, but a decorator could help there:
from functools import wraps
def pathrouted(f):
@wraps
def wrapped(self, *args, **kwargs):
# call the wrapped version first, ignore return value, in case this
# sets self.path or has other side effects
f(self, *args, **kwargs)
# then pick the class from the MRO as named by path, and call the
# original version
cls = next(c for c in type(self).__mro__ if c.__name__ == self.path)
return getattr(cls, f.__name__)(self, *args, **kwargs)
return wrapped
then use that on empty methods on your class:
class C(A, B):
@pathrouted
def __init__(self, path):
self.path = path
# either A.__init__ or B.__init__ will be called next
@pathrouted
def something(self):
pass # doesn't matter, A.something or B.something is called too
This is, however, becoming very unpythonic and ugly.
回答2:
While Martijn's answer is (as usual) close to perfect, I'd just like to point out that from a design POV, inheritance is the wrong tool here.
Remember that implementation inheritance is actually a static and somehow restricted kind of composition/delegation, so as soon as you want something more dynamic the proper design is to eschew inheritance and go for full composition/delegation, canonical examples being the State and the Strategy patterns. Applied to your example, this might look something like:
class C(object):
def __init__(self, strategy):
self.strategy = strategy
def something(self):
return self.strategy.something(self)
class AStrategy(object):
def something(self, owner):
print("Function A")
class BStrategy(object):
def __init__(self):
self.c = "something"
def something(self, owner):
print("B function with %s" % self.c)
if __name__ == '__main__':
a = C(AStrategy())
a.something()
b = C(BStrategy())
b.something()
Then if you need to allow the user to specify the strategy by name (as string), you can add the factory pattern to the solution
STRATEGIES = {
"A": AStrategy,
"B": BStrategy,
}
def cfactory(strategy_name):
try:
strategy_class = STRATEGIES[strategy_name]
except KeyError:
raise ValueError("'%s' is not a valid strategy" % strategy_name)
return C(strategy_class())
if __name__ == '__main__':
a = cfactory("A")
a.something()
b = cfactory("B")
b.something()
回答3:
Martijn's answer explained how to choose an object inheriting from one of two classes. Python also allows to easily forward a method to a different class:
>>> class C:
parents = { 'A': A, 'B': B }
def __init__(self, path):
self.parent = C.parents[path]
self.parent.__init__(self, path) # forward object initialization
def something(self):
self.parent.something(self) # forward something method
>>> ca = C('A')
>>> cb = C('B')
>>> ca.something()
Function A
>>> cb.something()
B function with something
>>> ca.path
'A'
>>> cb.path
'B'
>>> cb.c
'something'
>>> ca.c
Traceback (most recent call last):
File "<pyshell#46>", line 1, in <module>
ca.c
AttributeError: 'C' object has no attribute 'c'
>>>
But here class C does not inherit from A or B:
>>> C.__mro__
(<class '__main__.C'>, <class 'object'>)
Below is my original solution using monkey patching:
>>> class C:
parents = { 'A': A, 'B': B }
def __init__(self, path):
parent = C.parents[path]
parent.__init__(self, path) # forward object initialization
self.something = lambda : parent.something(self) # "borrow" something method
it avoids the parent attribute in C class, but is less readable...
来源：https://stackoverflow.com/questions/50036737/multiple-python-class-inheritance