问题
<?php
$file_name = $_FILES['files']['name'];
$tmp_name = $_FILES['files']['tmp_name'];
$file_size = $_FILES['files']['size'];
$file_type = $_FILES['files']['type'];
// The codes written above work fine and have proper information.
$fp = fopen($tmp_name, 'r'); // This one crashes.
$file_content = fread($fp, $file_size) or die("Error: cannot read file");
$file_content = mysql_real_escape_string($file_content) or die("Error: cannot read file");
fclose($fp);
....
I'm a newbie to PHP stuff. I'm trying to store a jpg image as blob in a database but terribly struggling with it :( I tried many tutorials and read documents but still no luck. Any suggestions or tutorials that might help me out..?
回答1:
When opening binary files with fopen(), use the rb mode, ie
$fp = fopen($tmp_name, 'rb');
Alternatively, you may simply use file_get_contents(), eg
$file_content = file_get_contents($tmp_name);
To enable better error reporting, place this at the top of your script
ini_set('display_errors', 'On');
error_reporting(E_ALL);
来源：https://stackoverflow.com/questions/7845233/how-to-convert-jpg-image-to-proper-blob-data-type-using-php