jQuery find all id's that begin with a defined string and end in a number

问题

I would like to do something like this:

jqueryElement.find('divIdWithIterator**').each(...);

where 'divIdWithIterator**' matches all elements with ids that start with 'divIdWithIterator' and end in a number, such as:

divIdWithIterator1, divIdWithIterator2, divIdWithIterator26

What is a good way to do this in jQuery?

Thanks!

回答1:

Unfortunately, there is no regular expression selector.

You could use the attribute-starts-with selector, then filter the results and check for numeric endings using search()

Eg

var divs = jqueryElement.find('[id^="divIdWithIterator"]').filter(function(index){
    return this.id.search(/\d$/) != -1;
});

回答2:

Following: http://api.jquery.com/attribute-starts-with-selector/

To find the elements whose id begin with "divIdWithIterator":

$('input[id^="divIdWithIterator"]')

And then avoid to have other elements that begin with "divIdWithIterator" and you don't want to select

来源：https://stackoverflow.com/questions/5878342/jquery-find-all-ids-that-begin-with-a-defined-string-and-end-in-a-number