问题
I want test an example method with scalar type hinting and strict types in PHP7. When I don't pass an argument, the method should throw a TypeError. PHPSpec return fatal error:
Uncaught TypeError: Argument 1 passed to Example::test
<?php
class Example
{
public function test(string $name)
{
$this->name = $name;
}
}
class ExampleSpec extends ObjectBehavior
{
function it_is_initializable()
{
$this->shouldHaveType('Test\Example');
}
function it_check_test_method_when_not_pass_argument()
{
$this->shouldThrow('\TypeError')->during('test');
}
}
At the beginning I declare: declare(strict_types=1);
What is wrong? How do I test throwing TypeError?
回答1:
For me it works if I annotate the unit test with this:
/**
* @expectedException \TypeError
*/
Then my test is green.
回答2:
Upon further investigation, this is a PHPSpec bug, and has been reported here. The bug hasn't been fixed in several months, so I would suggest commenting on it.
If you look at the code in src/PhpSpec/Matcher/ThrowMatcher.php, you can see that PHPSpec catches Exceptions that inherit 'Exception' and then checks the instance type of that exception. But, TypeError doesn't inherit from Exception, it inherits from Error. The only thing it has in common with an Exception, is that they both implement the Throwable interface.
For example:
101 public function verifyPositive($callable, array $arguments, $exception = null)
102 {
103 try {
104 call_user_func_array($callable, $arguments);
105 } catch (\Exception $e) {
106 if (null === $exception) {
107 return;
108 }
109
110 if (!$e instanceof $exception) {
111 throw new FailureException(sprintf(
112 'Expected exception of class %s, but got %s.',
113 $this->presenter->presentValue($exception),
114 $this->presenter->presentValue($e)
115 ));
116 }
Report the bug, explain these details, and show them this documentation about the inheritance of TypeError.
来源:https://stackoverflow.com/questions/34568723/phpspec-catching-typeerror-in-php7