checking if character is upper or lower case in alphanumeric

问题

I have this C code. If I input a LOL123 it should display that it is uppercase. And lol123 it is in lowercase. How do I use isalpha in excluding non-numerical input when checking isupper or is lower?

#include <stdio.h>

#define SIZE 6
char input[50];
int my_isupper(char string[]);

int main(){
    char input[] = "LOL123";
    int m;

    m= isupper(input);
    if( m==1){
        printf("%s is all uppercase.\n", input);
    }else
        printf("%s is not all uppercase.\n", input);

    return 0;
}

int my_isupper(char string[]){
    int a,d;

    for (a=0; a<SIZE); a++){
        d= isupper(string[a]) ; 
    }

    if(d != 0)
        d=1;

    return d;
}

回答1:

For upper-case function just loop trough the string and if a lowercase character is encountred you return false like value. And don't use standard library functions names to name your own functions. Use isUpperCase instead.

Live Demo: https://eval.in/93429

#include <stdio.h>
#include <string.h>

int isUpperCase(const char *inputString);

int main(void)
{
    char inputString1[] = "LOL123";
    char inputString2[] = "lol123";
    printf("%s is %s\n", inputString1, isUpperCase(inputString1)?"upper-case":"not upper-case");
    printf("%s is %s\n", inputString2, isUpperCase(inputString2)?"lower-case":"not upper-case");
    return 0;
}

int isUpperCase(const char *inputString)
{
    int i;
    int len = strlen(inputString);
    for (i = 0; i < len; i++) {
        if (inputString[i] >= 'a' && inputString[i] <= 'z') {
            return 0;
        }
    }
    return 1;
}

回答2:

int my_isalpha_lower(int c) {
    return ((c >= 'a' && c <= 'z')); } 

int my_isalpha_upper(int c) {
        return ((c >= 'A' && c <= 'Z')); } 

int isdigit(int c) {
        return (c >= '0' && c <= '9'); }



while (*s) {

     if (!is_digit(*s) && !my_isalpha_lower(*s)) 
     {
         //isnot lower but is alpha 
     }
     else if (!is_digit(*s) && !my_alpha_upper(*s))
     {
        //is not upper but is alpha 
     }

     s++;

}

回答3:

char c = ...;
if (isalpha(c))
{ 
     // do stuff if it's alpha
} else {
     // do stuff when not alpha
}

回答4:

You have a lot to learn, besides using a name of a standard function your design also is completely flawed. You only memorize the case of the last character that you encounter in your for loop, so the result that you return is not at all what you think.

Some more observations:

Don't use the name of a standard function for your own.
Arrays decay to pointers when then are used as function parameters. You have no way to automatically detect the size of the array.
You expect your return from isupper to be a logical value. Testing that again with ==1 makes not much sense.
You have two different variables called input, one in file scope, one in main.

回答5:

Fairly simple:

#include <ctype.h>

/**
 * Will return true if there's at least one alpha character in 
 * the input string *and* all alpha characters are uppercase.
 */
int allUpper( const char *str )
{
  int foundAlpha = 0;                   
  int upper = 1;

  for ( const char *p = str; *p; p++ )
  {
    int alpha = isalpha( *p );           
    foundAlpha = foundAlpha || alpha;    
    if ( alpha )
      upper = upper && isupper( *p );    
  } 

  return foundAlpha && upper; 
}

来源：https://stackoverflow.com/questions/21288752/checking-if-character-is-upper-or-lower-case-in-alphanumeric

标签

char

uppercase