Sklearn StratifiedKFold: ValueError: Supported target types are: ('binary', 'multiclass'). Got 'multilabel-indicator' instead

|▌冷眼眸甩不掉的悲伤 提交于 2019-12-09 14:34:57

问题


Working with Sklearn stratified kfold split, and when I attempt to split using multi-class, I received on error (see below). When I tried and split using binary, it works no problem.

num_classes = len(np.unique(y_train))
y_train_categorical = keras.utils.to_categorical(y_train, num_classes)
kf=StratifiedKFold(n_splits=5, shuffle=True, random_state=999)

# splitting data into different folds
for i, (train_index, val_index) in enumerate(kf.split(x_train, y_train_categorical)):
    x_train_kf, x_val_kf = x_train[train_index], x_train[val_index]
    y_train_kf, y_val_kf = y_train[train_index], y_train[val_index]

ValueError: Supported target types are: ('binary', 'multiclass'). Got 'multilabel-indicator' instead.

回答1:


keras.utils.to_categorical produces a one-hot encoded class vector, i.e. the multilabel-indicator mentioned in the error message. StratifiedKFold is not designed to work with such input; from the split method docs:

split(X, y, groups=None)

[...]

y : array-like, shape (n_samples,)

The target variable for supervised learning problems. Stratification is done based on the y labels.

i.e. your y must be a 1-D array of your class labels.

Essentially, what you have to do is simply to invert the order of the operations: split first (using your intial y_train), and convert to_categorical afterwards.




回答2:


I bumped into the same problem and found out that you can check the type of the target with this util function:

from sklearn.utils.multiclass import type_of_target
type_of_target(y)

'multilabel-indicator'

From its docstring:

  • 'binary': y contains <= 2 discrete values and is 1d or a column vector.
  • 'multiclass': y contains more than two discrete values, is not a sequence of sequences, and is 1d or a column vector.
  • 'multiclass-multioutput': y is a 2d array that contains more than two discrete values, is not a sequence of sequences, and both dimensions are of size > 1.
  • 'multilabel-indicator': y is a label indicator matrix, an array of two dimensions with at least two columns, and at most 2 unique values.

With LabelEncoder you can transform your classes into an 1d array of numbers (given your target labels are in an 1d array of categoricals/object):

from sklearn.preprocessing import LabelEncoder

label_encoder = LabelEncoder()
y = label_encoder.fit_transform(target_labels)



回答3:


Call to split() like this:

for i, (train_index, val_index) in enumerate(kf.split(x_train, y_train_categorical.argmax(1))):
    x_train_kf, x_val_kf = x_train[train_index], x_train[val_index]
    y_train_kf, y_val_kf = y_train[train_index], y_train[val_index]



回答4:


In my case, x was a 2D matrix, and y was also a 2d matrix, i.e. indeed a multi-class multi-output case. I just passed a dummy np.zeros(shape=(n,1)) for the y and the x as usual. Full code example:

import numpy as np
from sklearn.model_selection import RepeatedStratifiedKFold
X = np.array([[1, 2], [3, 4], [1, 2], [3, 4], [3, 7], [9, 4]])
# y = np.array([0, 0, 1, 1, 0, 1]) # <<< works
y = X # does not work if passed into `.split`
rskf = RepeatedStratifiedKFold(n_splits=3, n_repeats=3, random_state=36851234)
for train_index, test_index in rskf.split(X, np.zeros(shape=(X.shape[0], 1))):
    print("TRAIN:", train_index, "TEST:", test_index)
    X_train, X_test = X[train_index], X[test_index]
    y_train, y_test = y[train_index], y[test_index]


来源:https://stackoverflow.com/questions/48508036/sklearn-stratifiedkfold-valueerror-supported-target-types-are-binary-mul

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