问题
I'm trying to write kotlin code like:
for (byte b : hash)
stringBuilder.append(String.format("%02x", b&0xff));
but I have nothing to do with the "&". I'm trying to use "b and 0xff" but it doesn't work. The bitwise "and" seems to work on Int, not byte.
java.lang.String.format("%02x", (b and 0xff))
it's ok to use
1 and 0xff
回答1:
Kolin provides bitwise operator-like infix functions available for Int and Long only.
So it's necessary to convert bytes to ints to perform bitwise ops:
val b : Byte = 127
val res = (b.toInt() and 0x0f).toByte() // evaluates to 15
UPDATE: Since Kotlin 1.1 these operations are available directly on Byte.
From bitwiseOperations.kt:
@SinceKotlin("1.1")
public inline infix fun Byte.and(other: Byte): Byte = (this.toInt() and other.toInt()).toByte()
回答2:
Bitwise "and" of any byte-value and 0xff will always return the original value.
It is simple to see this if you draw the bits in a diagram:
00101010 42
11111111 and 0xff
--------
00101010 gives 42
来源:https://stackoverflow.com/questions/33411476/bitwise-doesnt-work-with-bytes-in-kotlin