问题
While in other statements like if ... else you can avoid braces if there is only one instruction in a block, you cannot do that with try ... catch blocks: the compiler doesn't buy it. For instance:
try
do_something_risky();
catch (...)
std::cerr << "Blast!" << std::endl;
With the code above, g++ simply says it expects a '{' before do_something_risky(). Why this difference of behavior between try ... catch and, say, if ... else ?
Thanks!
回答1:
Straight from the C++ spec:
try-block:
try compound-statement handler-seq
As you can see, all try-blocks expect a compound-statement. By definition a compound statement is multiple statements wrapped in braces.
Have everything in a compound-statement ensures that a new scope is generated for the try-block. It also makes everything slightly easier to read in my opinion.
You can check it yourself on page 359 of the C++ Language Specification
回答2:
Not sure why, but one benefit is that there is no dangling-catch issue. See dangling-else for an ambiguity that can arise when braces are optional.
回答3:
The syntax of try-block is:
try compound-statement handler-sequence
where handler-sequence is a sequence of one or more handlers, which have the following syntax:
catch (type-specifier-seq declarator) compound-statement
catch (...) compound-statement
This is different from other statements like control statements (if, while, for, etc). The syntax for these are:
if (condition) statement-true else statement-false
while (condition) statement
for (init-statement; condition; iteration_expression) statement
etc.
Now, The question is why compound-statement is needed in the try-block instead of a single statement?
Think about this code:
int main()
{
// before try-statement.
try g(); catch (std::runtime_error e) handleError(e);
// after try-statement.
}
I know, catch by value is a bad practice (e.g. possible object slicing, etc), but I did it in order to prevent a discussion about the storage duration of the exception and make it easy to reason about.
Now think, about the storage duration and linkage of 'e'. What you expect, is that 'e' only can be referred just before the call to handleError function, but no after the call is completed. It should have automatic storage duration and no linkage in this "scope". This could probably done by implicitly define a local scope like in other statements, but make the exception-declaration looks like a function parameter was probably a better idea. So the block (compound-statement) is needed. Se bellow.
Now think about the try and the statement after that. There is no reason to use the keyword try there, and no reason to use a compound statement, but the syntax could become ambiguous and complicated.
This is what Stroustrup said about it in Exception Handling for C++:
It might be possible to simplify the
try { ... } catch (abc) { ... }
syntax by removing the apparently redundant try keyword,
removing the redundant parentheses, and by allowing a handler
to be attached to any statement and not just to a block. For
example, one might allow:
void f()
{
g(); catch (x1) { /* ... */ }
}
as an alternative to - 28 -
void f()
{
try { g(); } catch (x1) { /* ... */ }
}
The added notational convenience seems insignificant and may not
even be convenient. People seem to prefer syntactic constructs that
start with a prefix that alerts them to what is going on, and it may
be easier to generate good code when the try keyword is required.
And after a more detailed explanation:
Allowing exception handlers to be attached to blocks only and not to
simple statements simplifies syntax analysis (both for humans and
computers) where several exceptions are caught and where nested
exception handlers are considered (see Appendix E). For example,
assuming that we allowed handlers to be attached to any statement
we could write:
try try f(); catch (x) { ... } catch (y) { ... } catch (z) { ... }
The could be interpreted be in at least three ways:
try { try f(); catch (x) { ... } } catch (y) { ... } catch (z) { ... }
try { try f(); catch (x) { ... } catch (y) { ... } } catch (z) { ... }
try { try f(); catch (x) { ... } catch (y) { ... } catch (z) { ... } }
There seems to be no reason to allow these ambiguities even if there
is a trivial and systematic way for a parser to chose one
interpretation over another. Consequently, a { is required after a
try and a matching } before the first of the associated sequence of
catch clauses.
As Stroustrup said, without the braces, the statement could mean different things depending on the rule and you will probably need to put braces to clarify the intension. Can we make some that looks complicated with the if-statement like in Stroustrup's example? Of course we can, something like this for example:
if (c1) if (c2) f(); else if (c3) g(); else h();
This is actually equivalent to:
if (c1) { if (c2) f(); else { if (c3) g(); else h(); } }
But I think this is less problematic than the case of try-block. There is two syntax for the if-statament:
if (condition) statement-true
if (condition) statement-true else statement-false
because it make sense not to have a else action sometimes. But it make no sense a try-block without a catch-clause. The 'try' can be omitted but not practical, as Stroustrup said, but the catch-clause can not if you specified a try-block. Beside of this, there could be more than one catch related to the same try-block but only one is executed based in rules that depends on the exception type and order of the catch-clauses.
Now, what if the syntax of if-else is changed to:
if (condition) compound-statement-true else compound-statement-false
then, you must write if-else like this:
if (c1) { f(); } else { if (c2) { g(); } else { h(); } }
See that there is no 'elseif' keyword, no special syntax for 'else if'. I think that even the 'put braces always' defenders don't like to write like this, and write this instead:
if (c1) { f(); } else if (c2) { g(); } else { h(); }
I think that this is not a strong reason to define the syntax as above and introduce in the language a 'elseif' keyword or define a special syntax for 'else if'.
回答4:
Read this link. Most of the reason appears to be about managing the scope and allocation of objects that need to be created and destroyed in case of real exceptions.
So, my guess is, the grammar writers of C++ are asking the authors of g++(or any standards complying C++ compiler) to prepare it for the worst possible cases, and g++ authors appear to have done so.
回答5:
Why? A tradeoff between safety and backwards compatibility.
The lessons learnt from if...else showed that requiring braces eliminates errors. Now, the ISO C++ people have a strong preference for backwards compatibility with C, so they didn't change the C syntax for if...else. But new constructs require braces to demarcate controlled blocks, as they won't appear in old C code and therefore backwards compatibility is not a concern.
回答6:
Well, first, that's how the grammar works.
Second, I would believe that the goal is to forcibly generate a new scope for the exception blocks(correct me if I'm wrong).
回答7:
That's how they wanted to be. There is no justification, it's a law.
回答8:
Not sure if you're using .NET but the CLR uses the braces as flags.
http://dotnet.sys-con.com/node/44398
From the article: "The SEH (structure exception handling) table consists of a set of clauses that describe the structure of the guarded code. The table has a set of binary flags that describe the type of exception handling clause: a Try Offset flag, which is the beginning of the guarded code block; a Try Length flag, which is the length of the guarded code; Handler Offset and Handler Length flags, which detail the beginning of the exception handler block and its length; and a Class Token or Filter Offset flag, depending on the type of Exception Handler that was defined. This information allows the CLR to determine what to do when an exception occurs. It maps out the beginning of the guarded code block, the code to execute for an exception, and special semantics related to filtering or other special circumstance."
I would assume that other frameworks do the same thing.
回答9:
Mainly it's because
if (a)
int b = 10;
else
int b = 5;
b += 5;
Will fail because the if...else without {} is a syntax shortcut for this
if (a) {
int b = 10;
} else {
int b = 5;
}
b += 5;
which explicitly tells you that int b is in a different scope than the rest of the software.
If I'm not mistaken the following also fails
a ? int b = 10 : int b = 5;
b += 5;
Granted, your compiler might optimize that code for you... but it should technically fail because of the scopes in the if/else statement.
Whenever you see {} you're defining the scope of the software.
-Stephen
来源：https://stackoverflow.com/questions/3008937/why-do-try-catch-blocks-require-braces