问题
I know there are many questions of this ilk with many answers.
I know that I can use
var popup = window.open('');
and can later use
popup.close();
to close that window.
However, is there a way to close all children without having to store the window.open result?
That is, could I do
window.open('1');
window.open('2');
window.open('3');
and then somehow do a global "Close" call that will close these three windows?
If not, could I accomplish it by using the following code to do the open?
window.open('1','window1');
window.open('2','window2');
window.open('3','window3');
回答1:
You can make a new function that basically wraps the existing functionality with what you're trying to do.
var WindowDialog = new function() {
this.openedWindows = {};
this.open = function(instanceName) {
var handle = window.open(Array.prototype.splice.call(arguments, 1));
this.openedWindows[instanceName] = handle;
return handle;
};
this.close = function(instanceName) {
if(this.openedWindows[instanceName])
this.openedWindows[instanceName].close();
};
this.closeAll = function() {
for(var dialog in this.openedWindows)
this.openedWindows[dialog].close();
};
};
Sample Usage
WindowDialog.open('windowName', /* arguments you would call in window.open() */);
WindowDialog.open('anotherName', /* ... */);
WindowDialog.open('uniqueWindow', /* ... */);
WindowDialog.open('testingAgain', /* ... */);
WindowDialog.open('finalWindow', /* ... */);
// closes the instance you created with the name 'testingAgain'
WindowDialog.close('testingAgain');
// close all dialogs
WindowDialog.closeAll();
回答2:
try this to open and close
document.MyActiveWindows= new Array;
function openWindow(sUrl,sName,sProps){
document.MyActiveWindows.push(window.open(sUrl,sName,sProps))
}
function closeAllWindows(){
for(var i = 0;i < document.MyActiveWindows.length; i++)
document.MyActiveWindows[i].close()
}
来源:https://stackoverflow.com/questions/17756376/close-all-pop-up-windows