问题
As Python newbie I recently discovered that with Py 2.7 I can do something like:
print '{:20,.2f}'.format(123456789)
which will give the resulting output:
123,456,789.00
I'm now looking to have a similar outcome for a pandas df so my code was like:
import pandas as pd
import random
data = [[random.random()*10000 for i in range(1,4)] for j in range (1,8)]
df = pd.DataFrame (data)
print '{:20,.2f}'.format(df)
In this case I have the error:
Unknown format code 'f' for object of type 'str'
Any suggestions to perform something like '{:20,.2f}'.format(df) ?
As now my idea is to index the dataframe (it's a small one), then format each individual float within it, might be assign astype(str), and rebuild the DF ... but looks so looks ugly :-( and I'm not even sure it'll work ..
What do you think ? I'm stuck ... and would like to have a better format for my dataframes when these are converted to reportlabs grids.
回答1:
import pandas as pd
import numpy as np
data = np.random.random((8,3))*10000
df = pd.DataFrame (data)
pd.options.display.float_format = '{:20,.2f}'.format
print(df)
yields (random output similar to)
0 1 2
0 4,839.01 6,170.02 301.63
1 4,411.23 8,374.36 7,336.41
2 4,193.40 2,741.63 7,834.42
3 3,888.27 3,441.57 9,288.64
4 220.13 6,646.20 3,274.39
5 3,885.71 9,942.91 2,265.95
6 3,448.75 3,900.28 6,053.93
The docstring for pd.set_option or pd.describe_option explains:
display.float_format: [default: None] [currently: None] : callable
The callable should accept a floating point number and return
a string with the desired format of the number. This is used
in some places like SeriesFormatter.
See core.format.EngFormatter for an example.
来源:https://stackoverflow.com/questions/18404946/py-pandas-formatdataframe