requests.HTTPError uncaught after a requests.get() 404 response

问题

I'm having a slight problem with the requests library.

Say for example I have a statement like this in Python:

try:
   request = requests.get('google.com/admin') #Should return 404

except requests.HTTPError, e:
   print 'HTTP ERROR %s occured' % e.code

For some reason the exception is not being caught. I've checked the API documentation for requests but it's a bit slim. Is there anyone who has more experience with the library that might be able to help me out?

回答1:

Interpreter is your friend:

import requests
requests.get('google.com/admin')
# MissingSchema: Invalid URL u'google.com/admin': No schema supplied

Also, requests exceptions:

import requests.exceptions
dir(requests.exceptions)

Also notice that by default requests doesn't raise exception if status is not 200:

In [9]: requests.get('https://google.com/admin')
Out[9]: <Response [503]>

There is raise_for_status() method that does it:

In [10]: resp = requests.get('https://google.com/admin')

In [11]: resp
Out[11]: <Response [503]>

In [12]: resp.raise_for_status()
  ...
HTTPError: 503 Server Error: Service Unavailable

回答2:

Running your code in python 2.7.5:

import requests

try:
  response = requests.get('google.com/admin') #Should return 404
except requests.HTTPError, e:
  print 'HTTP ERROR %s occured' % e.code
  print e

Results in:

File "C:\Python27\lib\site-packages\requests\models.py", line 291, in prepare_url raise MissingSchema("Invalid URL %r: No schema supplied" % url) requests.exceptions.MissingSchema: Invalid URL u'google.com/admin': No schema supplied

To get your code to pick up this exception you need to add:

  except (requests.exceptions.MissingSchema) as e:
    print 'Missing schema occured. status'
    print e

Note also it is not a missing schema but a missing scheme.

来源：https://stackoverflow.com/questions/16206062/requests-httperror-uncaught-after-a-requests-get-404-response