问题
I was running TensorFlow and I happen to have something yielding a NaN. I'd like to know what it is but I do not know how to do this. The main issue is that in a "normal" procedural program I would just write a print statement just before the operation is executed. The issue with TensorFlow is that I cannot do that because I first declare (or define) the graph, so adding print statements to the graph definition does not help. Are there any rules, advice, heuristics, anything to track down what might be causing the NaN?
In this case I know more precisely what line to look at because I have the following:
Delta_tilde = 2.0*tf.matmul(x,W) - tf.add(WW, XX) #note this quantity should always be positive because its pair-wise euclidian distance
Z = tf.sqrt(Delta_tilde)
Z = Transform(Z) # potentially some transform, currently I have it to return Z for debugging (the identity)
Z = tf.pow(Z, 2.0)
A = tf.exp(Z)
when this line is present I have it that it returns NaN as declared by my summary writers. Why is this? Is there a way to at least explore what value Z has after its being square rooted?
For the specific example I posted, I tried tf.Print(0,Z) but with no success it printed nothing. As in:
Delta_tilde = 2.0*tf.matmul(x,W) - tf.add(WW, XX) #note this quantity should always be positive because its pair-wise euclidian distance
Z = tf.sqrt(Delta_tilde)
tf.Print(0,[Z]) # <-------- TF PRINT STATMENT
Z = Transform(Z) # potentially some transform, currently I have it to return Z for debugging (the identity)
Z = tf.pow(Z, 2.0)
A = tf.exp(Z)
I actually don't understand what tf.Print is suppose to do. Why does it need two arguments? If I want to print 1 tensor why would I need to pass 2? Seems bizarre to me.
I was looking at the function tf.add_check_numerics_ops() but it doesn't say how to use it (plus the docs seem to not be super helpful). Does anyone know how to use this?
Since I've had comments addressing the data might be bad, I am using standard MNIST. However, I am computing a quantity that is positive (pair-wise eucledian distance) and then square rooting it. Thus, I wouldn't see how the data specifically would be an issue.
回答1:
There are a couple of reasons WHY you can get a NaN-result, often it is because of too high a learning rate but plenty other reasons are possible like for example corrupt data in your input-queue or a log of 0 calculation.
Anyhow, debugging with a print as you describe cannot be done by a simple print (as this would result only in the printing of the tensor-information inside the graph and not print any actual values).
However, if you use tf.print as an op in bulding the graph (tf.print) then when the graph gets executed you will get the actual values printed (and it IS a good exercise to watch these values to debug and understand the behavior of your net).
However, you are using the print-statement not entirely in the correct manner. This is an op, so you need to pass it a tensor and request a result-tensor that you need to work with later on in the executing graph. Otherwise the op is not going to be executed and no printing occurs. Try this:
Z = tf.sqrt(Delta_tilde)
Z = tf.Print(Z,[Z], message="my Z-values:") # <-------- TF PRINT STATMENT
Z = Transform(Z) # potentially some transform, currently I have it to return Z for debugging (the identity)
Z = tf.pow(Z, 2.0)
回答2:
I used to find it's much tougher to pinpoint where the nans and infs may occur than to fix the bug. As a complementary to @scai's answer, I'd like to add some points here:
The debug module, you can imported by:
from tensorflow.python import debug as tf_debug
is much better than any print or assert.
You can just add the debug function by changing your wrapper you session by:
sess = tf_debug.LocalCLIDebugWrapperSession(sess)
sess.add_tensor_filter("has_inf_or_nan", tf_debug.has_inf_or_nan)
And you'll prompt an command line interface, then you enter:
run -f has_inf_or_nan and lt -f has_inf_or_nan to find where the nans or infs are. The first one is the first place where the catastrophe occurs. By the variable name you can trace the origin in your code.
Reference: https://developers.googleblog.com/2017/02/debug-tensorflow-models-with-tfdbg.html
回答3:
It look like you can call it after you complete making the graph.
check = tf.add_check_numerics_ops()
I think this will add the check for all floating point operations. Then in the sessions run function you can add the check operation.
sess.run([check, ...])
回答4:
As of version 0.12, TensorFlow is shipped with a builtin debugger called tfdbg. It optimizes the workflow of debugging this type of bad-numerical-value issues (like inf and nan). The documentation is at:
https://www.tensorflow.org/programmers_guide/debugger
回答5:
First of all, you need to check you input data properly. In most cases this is the reason. But not always, of course.
I usually use Tensorboard to see whats happening while training. So you can see the values on each step with
Z = tf.pow(Z, 2.0)
summary_z = tf.scalar_summary('z', Z)
#etc..
summary_merge = tf.merge_all_summaries()
#on each desired step save:
summary_str = sess.run(summary_merge)
summary_writer.add_summary(summary_str, i)
Also you can simply eval and print the current value:
print(sess.run(Z))
回答6:
Current implementation of tfdbg.has_inf_or_nan seems do not break immediately on hitting any tensor containing NaN. When it does stop, the huge list of tensors displayed are not sorted in order of its execution.
A possible hack to find the first appearance of Nans is to dump all tensors to a temporary directory and inspect afterwards.
Here is a quick-and-dirty example to do that. (Assuming the NaNs appear in the first few runs)
回答7:
I was able to fix my NaN issues by getting rid of all of my dropout layers in the network model. I suspected that maybe for some reason a unit (neuron?) in the network lost too many input connections (so it had zero after the dropout), so then when information was fed through, it had a value of NaN. I don't see how that could happen over and over again with dropout=0.8 on layers with more than a hundred units each, so the problem was probably fixed for a different reason. Either way, commenting out the dropout layers fixed my issue.
EDIT: Oops! I realized that I added a dropout layer after my final output layer which consists of three units. Now that makes more sense. So, don't do that!
回答8:
For TensorFlow 2, inject some x=tf.debugging.check_numerics(x,'x is nan') into your code. They will throw an InvalidArgument error if xhas any values that are not a number (NaN) or infinity (Inf).
Oh and for the next person finding this when hunting a TF2 NaN issue, my case turned out to be an exploding gradient. The gradient itself got to 1e+20, which was not quite NaN yet, but adding that to the variable then turned out too big. The diagnosis that I did was
gradients = tape.gradient(loss, training_variables)
for g,v in zip(gradients, training_variables):
tf.print(v.name, tf.reduce_max(g))
optimizer.apply_gradients(zip(gradients, training_variables))
which revealed the overly large numbers. Running the exact same network on CPU worked fine, but it failed on the GTX 1080 TI in my workstation, thus making a CUDA numerical stability issue likely as the root cause. But since it only occurred sometimes, I duct-taped the whole thing by going with:
gradients = tape.gradient(loss, training_variables)
gradients = [tf.clip_by_norm(g, 10.0) for g in gradients]
optimizer.apply_gradients(zip(gradients, training_variables))
which will just clip exploding gradients to a sane value. For a network where gradients are always high, that wouldn't help, but since the magnitudes where high only sporadically, this fixed the problem and now the network trains nicely also on GPU.
来源：https://stackoverflow.com/questions/38810424/how-does-one-debug-nan-values-in-tensorflow