Using Impala get the count of consecutive trips

Sample Data

touristid|day
ABC|1
ABC|1
ABC|2
ABC|4
ABC|5
ABC|6
ABC|8
ABC|10

The output should be

touristid|trip
ABC|4

Logic behind 4 is count of consecutive days distinct consecutive days sqq 1,1,2 is 1st then 4,5,6 is 2nd then 8 is 3rd and 10 is 4th I want this output using impala query

Get previous day using lag() function, calculate new_trip_flag if the day-prev_day>1, then count(new_trip_flag).

Demo:

with table1 as (
select 'ABC' as touristid, 1  as day union all
select 'ABC' as touristid, 1  as day union all
select 'ABC' as touristid, 2  as day union all
select 'ABC' as touristid, 4  as day union all
select 'ABC' as touristid, 5  as day union all
select 'ABC' as touristid, 6  as day union all
select 'ABC' as touristid, 8  as day union all
select 'ABC' as touristid, 10 as day 
)

select touristid, count(new_trip_flag) trip_cnt
  from 
       ( -- calculate new_trip_flag
         select touristid,
                case when (day-prev_day) > 1 or prev_day is NULL then true end  new_trip_flag
           from       
                ( -- get prev_day
                  select touristid, day, 
                         lag(day) over(partition by touristid order by day) prev_day
                    from table1
                )s
        )s
 group by touristid;

Result: